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Alexus [3.1K]
3 years ago
15

Msh

Mathematics
1 answer:
Rudiy273 years ago
3 0

a Anna drives her sisters at an a average of 60 mph and devive home

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5x+6y=18and 18x-15y=36<br> parallel or perpendicular
Katen [24]

Answer:

<u>They</u><u> </u><u>are</u><u> </u><u>neither</u><u> </u><u>parallel</u><u> </u><u>nor</u><u> </u><u>perpendicular</u><u>,</u><u> </u><u>since</u><u> </u><u>slope</u><u> </u><u>are</u><u> </u><u>different</u><u> </u><u>and</u><u> </u><u>not</u><u> </u><u>related</u><u> </u><u>by</u><u> </u><u>any</u><u> </u><u>equation</u>

Step-by-step explanation:

First arrange them according to general equation:

y = mx + c

<u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>f</u><u>i</u><u>r</u><u>s</u><u>t</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u> :

5x + 6y = 18 \\ 6y =  - 5x + 18 \\ { \boxed{y =  -  \frac{5}{6} x + 3}}

<u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u> :

18x - 15y = 36 \\ 15y = 18x - 36 \\ y =  \frac{18}{15} x -   \frac{12}{5}

8 0
3 years ago
From the first quiz to the second quiz, a score dropped eight points. The score on the second quiz was 39. What was the first qu
frutty [35]

Answer:47

Step-by-step explanation:

Because 39+8=47.

5 0
3 years ago
Read 2 more answers
What is 17/20 - 4/15
Zinaida [17]

Hello there, today you gave us the problem \frac{17}{20}-\frac{4}{15},

Our first step is to give them common denominators, which is \frac{51}{60}-\frac{16}{60}, solve it and we get \frac{35}{60} as our answer, which can be simplified down to \frac{7}{12}

4 0
3 years ago
Cal is measuring temperature changes in four substances over different time periods as part of a school project. Which data show
djyliett [7]

Answer:

C) The third table. K= 5

C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5

Step-by-step explanation:

1) Below there are the missing data:

A proportional relationship through a constant k. It is obtained when we divide:

k=\frac{y}{x}

2)In this case, when we divide the temperature (T) by the time (h).

k=\frac{T}{h}

3)So, examining the table below we are searching for a ratio k common to all measures (temperatures over hour).

A) \frac{12}{3}\neq\frac{25}{5}\neq\frac{36}{6}\neq\frac{81}{9}\\B) \frac{22.5}{3}\neq\frac{30}{4}\neq\frac{52.5}{7}\neq\frac{67.5}{8}\\C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5\\D)\frac{8.5}{2}\neq\frac{22.5}{5}\neq\frac{28.5}{7}\neq\frac{36}{8}

3 0
3 years ago
syliva weighed 8 pounds when she was born by her first birthday her weight had tripled by her second birthday she had gained 12
barxatty [35]
I'm pretttty sure it's 216
3 0
3 years ago
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