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jarptica [38.1K]
3 years ago
14

30 ft

Mathematics
2 answers:
Alex3 years ago
6 0

Answer:

32 ft

Step-by-step explanation:

find the area of the large rectangle:

30 x 16 = 480

find the area of the small rectangle:

10 x 8 = 80

subract the small rectangle from the big rectangle to get the area of the shaded region:

480 - 80 = 400

now plug this area and the height into the equation for triangle area:

A = bh/2

400 = b(25)/2 multiply both sides by 2

2(400) = 2(25b/2)

800 = 25b divide both sides by 25

800/25 = 25b/25

32 = b

sesenic [268]3 years ago
3 0

For this case we have that the area of the shaded region is given by the subtraction of the large rectangle minus the small rectangle.

A_ {sr} = 30 * 16-10 * 8\\A_ {sr} = 480-80\\A_ {sr} = 400

Thus, the area of the shaded region is 400 \ ft ^ 2

If the triangle must have the same area and a height of 25, then we have:

400 = \frac {1} {2} b * 25\\400 = 12.5b

Dividing between 12.5 on both sides of the equation:

b = 32

Thus, the base of the triangle is 32.

Answer:

32

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Answer:

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Step-by-step explanation:

we know that

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so

The total number of faces is 5 (one rectangular face plus four triangular faces)

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Suppose that a cyclist began a 374 mi ride across a state at the western edge of the​ state, at the same time that a car traveli
kherson [118]
This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
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374=11x+183.8837
collecting like term we get:
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11x=190.1163
thus;
x=(190.1163)/(11)
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4 0
3 years ago
Please help i need to finish this!!
s2008m [1.1K]

Answer:

20 inches x 26 inches

Step-by-step explanation:

set up an equation: (2x)(x+7)=520

now just solve it

2x^2+14x=520

x^2+7x-260 = 0

factor: (x-13)(x+20)

x = 13 and -20

13 is the only one that works because you can't have a negative side length

13+7=20

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3 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

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