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Ml

Tanya [424]

Answer:

The gold vein is 96 miles away from the farthest gold dust strike.

Step-by-step explanation:

Distance Between two Points in the Plane

Given two points A(x,y) and B(w,z), the distance between them is:

$d=\sqrt{(z-y)^2+(w-x)^2}$

The prospector positioned the gold vein at (-2,9) and the farthest gold dust strike at (94,9). We are required to calculate the distance between these two points. Use the formula:

$d=\sqrt{(9-9)^2+(94-(-2))^2}$

$d=\sqrt{0^2+96^2}$

$d=\sqrt{96^2}=96$

The distance is 96 units, but we know each unit on the graph represents 1 mile, thus the gold vein is 96 miles away from the farthest gold dust strike.

8 0

3 years ago

512−−−√3= what is the ANSWER HURRY

Tems11 [23]

512 root 3 equals 886.810

4 0

3 years ago

Find the length of the arc and express your answer as a fraction times pie

Elina [12.6K]

Solution:

Given a circle of center, A with radius, r (AB) = 6 units

Where, the area, A, of the shaded sector, ABC, is 9π

To find the length of the arc, firstly we will find the measure of the angle subtended by the sector.

To find the area, A, of a sector, the formula is

$\begin{gathered} A=\frac{\theta}{360\degree}\times\pi r^2 \\ Where\text{ r}=AB=6\text{ units} \\ A=9\pi\text{ square units} \end{gathered}$

Substitute the values of the variables into the formula above to find the angle, θ, subtended by the sector.

$\begin{gathered} 9\pi=\frac{\theta}{360\degree}\times\pi\times6^2 \\ Crossmultiply \\ 9\pi\times360=36\pi\times\theta \\ 3240\pi=36\pi\theta \\ Divide\text{ both sides by 36}\pi \\ \frac{3240\pi}{36\pi}=\frac{36\pi\theta}{36\pi} \\ 90\degree=\theta \\ \theta=90\degree \end{gathered}$

To find the length of the arc, s, the formula is

$\begin{gathered} s=\frac{\theta}{360\degree}\times2\pi r \\ Where \\ \theta=90\degree \\ r=6\text{ units} \end{gathered}$

Substitute the variables into the formula to find the length of an arc, s above

$\begin{gathered} s=\frac{\theta}{360}\times2\pi r \\ s=\frac{90\degree}{360\degree}\times2\times\pi\times6 \\ s=\frac{12\pi}{4}=3\pi\text{ units} \\ s=3\pi\text{ units} \end{gathered}$

Hence, the length of the arc, s, is 3π units.

4 0

1 year ago

Given the equation 4x2 − 8x + 20 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 + k =

GenaCL600 [577]

Answer:

The correct option is:

h = 1, k = 16

Step-by-step explanation:

y=4x^2-8x+20 =0

It is a quadratic formula in standard form:

ax^2+bx+c

where a = 4 , b = -8 and c=20

The vertex form is:

a(x − h)2 + k = 0

h is the axis of symmetry and (h,k) is the vertex.

Calculate h according to the following formula:

h = -b/2a

h= -(-8)/2(4)

h = 8/8

h = 1

Substitute k for y and insert the value of h for x in the standard form:

ax^2+bx+c

k = 4(1)^2+(-8)(1)+20

k = 4-8+20

k=-4+20

k = 16

Thus the correct option is h=1, k=16....

8 0

3 years ago

Find the measures of angles x and y please!?

kenny6666 [7]

Answer:

y: 139 x: 139 too

Step-by-step explanation:

5 0

3 years ago

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