Hope this helps bye bye thanks
Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
Step-by-step explanation:
because <u>c</u> is shorter than<u> a</u> we know C is a smaller angle than A
so the first choice is out.
use the law of cosines to find b
= 
=1681+400-1326.787871
= 754.21219
b= 
b= 27.46292
so the last choice looks good
Answer:
84 miles
Step-by-step explanation:
35% as a decimal is .35.
240*.35=84
The graph is shown in the attached image.