Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
Given:
The height h of an object after t seconds is

The height of a neighboring 50-foot tall building is modeled by the equation h=50.
The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.
To find:
The statement which describes the validity of these solutions.
Solution:
We have,

Here, t is the time in seconds.
For t=-2,



For t=5,



So, the value of h is 50 at t=-2 and t=5.
We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.
The solution t = 5 is the only valid solution to this system since time cannot be negative.
Therefore, the correct option is C.
2/5 is bigger and 3/8 is smaller
The answer is isosceles.
Explanation:
Isosceles triangle is where two side lengths are equal.
Equilateral triangle is where all side lengths are equal.
Scalene Triangle is where all side lengths have different measures.
Since this triangle has two side lengths with the same measure it is an isosceles triangle.