Original position of the submarine below the Surface = -2 2/3= -8/3
Submarine at a depth of -2 2/3 feet descended by 5 1/2 feet.
So new position of the Submarine = 
To Reach the surface submarine must rise = 0-(-49/6)
As seen from the equation the two negative sign [(-)(-)] will change into a positive sign.
At the surface the position of the submarine = +49/6 feet
The exact value of arcsin ( 2 √ 2 ) is π4.
Answer: It is TRUE. A point in a linear equation can be the solution to said equation.
Answer:
1.5, 1.05, 1.005
Step-by-step explanation:
the more 0's you have, the smaller the number will be.