Question

Find the limit of the function by using direct substitution. limit as x approaches one of quantity x squared plus three x minus one.

Answer 1

Answer:

Limit = -1

Step-by-step explanation:

We are given the following function:

$x^2 + 3x -1$

We are to calculate the limit of this function as x approaches zero.

For that, we will use direct substitution method and substitute the x with 0 in the given function to calculate its limit as follows:

$x ^ 2 + 3 x - 1$

$( 0 ) ^ 2 + 3 ( 0 ) - 1 = - 1$

Therefore, the limit is -1.