Dakari makes 2 dozen jars of jam. The total

Dedra used coupons 6 times at the store last month.

AVprozaik [17]

Answer:

The mean is 42, rounded to the nearest cant would be 42.00. IF this helped subscribe to Amiredagoat Yt

Step-by-step explanation:

6 0

3 years ago

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What is the volume of the following prism?

ira [324]

Answer: $\Large\boxed{B.~\displaystyle 75~m^3}$

Step-by-step explanation:

Given information

Height = 2 m

Base = 5 m

Length = 15 m

Given the formula for Triangular Prism Volume

$V~=~\displaystyle \frac{1}{2}\times ~b~\times~h~\times~l$

$\to V=Volume\\\to b=base\\\to h = height\\\to l = length$

Substitute values into the formula

$V~=~\displaystyle \frac{1}{2}\times ~(5)~\times~(2)~\times~(15)$

Simplify by multiplication

$V~=~\displaystyle \frac{5}{2}~\times ~30$

$\Large\boxed{V~=~\displaystyle 75~m^3}$

Hope this helps!! :)

Please let me know if you have any questions

3 0

1 year ago

Any help on this question?

elena-s [515]

Answer:

50%

Step-by-step explanation:

Total students = 12 + 18 + 6 = 36

Seventh-graders = 18

18/36*100 = 50%

3 0

3 years ago

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If (x-y)^2=71 and x^2+y^2=59 what is the value of xy?

Lena [83]

Solve the equations
first one
take the sqrt of both sides
x-y=√71
add y to both sides
x=y+√71
sub y+√71 for x in other part

(y+√71)²+y²=59
y²+2y√71+71+y²=59
2y²+2y√71+71=59
minus 59 both sides
2y²+2y√71+12=0
factor out 2
2(y²+y√71+6)=0
use quadratic equation or something
y= $\frac{- \sqrt{71}- \sqrt{47} }{2}$ and $\frac{- \sqrt{71}+ \sqrt{47} }{2}$

sub those for x

x=y+√71
note: √71=(2√71)/2

x= $\frac{- \sqrt{71}- \sqrt{47} +2\sqrt{71}}{2}$ , $\frac{\sqrt{71}- \sqrt{47}}{2}$
or
x= $\frac{- \sqrt{71}+ \sqrt{47} +2\sqrt{71}}{2}$ , $\frac{\sqrt{71}+ \sqrt{47}}{2}$

xy= $\frac{\sqrt{71}- \sqrt{47}}{2}$ times $\frac{-\sqrt{71}- \sqrt{47}}{2}$ or $\frac{\sqrt{71}+ \sqrt{47}}{2}$ times $\frac{-\sqrt{71}+ \sqrt{47}}{2}$

the result is -6 both times

xy=-6

5 0

4 years ago

Solve #118. Algebra ASAP

fredd [130]

To solve this, we need to set up two different equations, then use them to find what we are looking for.

First, we need to change the words in the problem into variables and numbers. "The length of a rectangle is 3mm less than four times the width." This translates into: L=4W-3

Now, we are given the area and are told to solve for the dimensions (meaning the height and width. We need to use the area equation for a rectangle to finish the problem. A=L x W

Substitute the equation we created for the length into the area equation and we can solve for the width.

A= L x W --> 1387=(4W-3) x W --> 1387=4W^2-3W --> 0=4W^2-3W-1387

0=4(W-19)(W+18.25)

So our width either equals 19 or -18.25, and since a distance can't really be negative, our width is 19mm. Now we can use this to solve for length.

L=4W-3 --> L=4(19)-3 --> L=76-3 --> L=73

Our length is 73 mm.

Check: We can check this answer by multiplying the two numbers to see if they provide the area given in the problem. A=73x19=1387mm^2

6 0

4 years ago