All categories

3 years ago

Dedra used coupons 6 times at the store last month.

Mathematics

2 answers:

AVprozaik [17]3 years ago

6 0

Answer:

The mean is 42, rounded to the nearest cant would be 42.00. IF this helped subscribe to Amiredagoat Yt

Step-by-step explanation:

rewona [7]3 years ago

6 0

What the guy above me said

You might be interested in

Can you help me solve systems of equations by elimination step by step 6x+y=15 -7x-2y=-10

Anna71 [15]

Answer: (4, -9)

Step-by-step explanation:

Use elimination method. Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable. I will be eliminating y

6x + y = 15 → 2(6x + y = 15) → 12x + 2y = 30

-7x - 2y = -10 → 1(-7x + 2y = -10) → -7x - 2y = -10

5x = 20

x = 4

Next, replace "x" with "4" into either equation and solve for y.

6(4) + y = 15

24 + y = 15

y = -9

Check:

Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.

-7x - 2y = -10

-7(4) - 2(-9) = -10

-28 - -18 = -10

-28 + 18 = -10

-10 = -10 $\checkmark$

6 0

4 years ago

Name

Eddi Din [679]

Answer:

104 Inches

Step-by-step explanation:

Alyssa's blanket contains 7 pink stripes and 6 white stripes.

Total Number of Stripes =7+6=13

Since each stripe is 8 inches wide.

The width of Alyssa's blanket will be the product of the number of stripes by the width of each stripe.

Therefore:

Width = 13 X 8 Inches =104 Inches

Alyssa's blanket is 104 Inches wide.

4 0

3 years ago

Please help quick! V=?

Stells [14]

Answer:

904.78

Step-by-step explanation:

we have the radius, which is 6.

were trying to find the volume.

the foemula for the v of a sphere is 4/3(pi)r^3

so, multiply 4/3 times pi and we get 4.18879.

find 6^3, which is 216. multiply tyese two values, and we get 904.77864.

so, the volume of this sphere is around 904.78

3 0

3 years ago

Let U= U= Universal set ={0, 1, 2, 3, 4, 5, 6, 7, 8, 9}={0, 1, 2, 3, 4, 5, 6, 7, 8, 9} , A={1, 3, 4, 5, 7, 9} A={1, 3, 4, 5, 7,

blagie [28]

Answer:

a) $A' = [0,2,6,8]$

b) $(AUB)' = [0,2,6]$

c) $(AUB')' = [9]$

d) A∩B′ $= [3,5,9]$

Step-by-step explanation:

Assuming this problem: "Let U= U= Universal set ={0, 1, 2, 3, 4, 5, 6, 7, 8, 9} , A={1, 3, 4, 5, 7, 9} , and B={1, 4, 7, 8} . List the elemetns of the following sets in the increasing order: a) A′= b) (A∪B)′={ , , }} c) (A∪B′)′={ }} d) A∩B′={ , , }}"

Part a

For this case we just need to find the elements in the universal set that are not in A. And we see that:

$A' = [0,2,6,8]$

And that represent the complement for A

Part b

For this case we need to find first the Union AUB who are the elements on A or B without repetition and we got:

$AUB = [1,3,4,5,7,8,9]$