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PolarNik [594]
4 years ago
9

The joints that allow the biggest amount of movements are called?

Mathematics
1 answer:
kolbaska11 [484]4 years ago
3 0
I think the ball and socket joints
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What is the value of 4 in the number 358.547? A) 0.0004 B) 0.004 C) 0.04 D) 4
LiRa [457]
The answer is C) 0.04 becuase the 4 is in the hundredths place
3 0
3 years ago
Read 2 more answers
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zloy xaker [14]

Answer: T= 1 and I’m not sure if 6t = 6

6 0
3 years ago
Write the equation of the line passing through the points (44,6) and (-4,-6)
Verizon [17]

Answer:

Y = 1/4x - 5

Step-by-step explanation:

Slope (m = y2-y1 / x2-x1) is 1/4 and using one point substituting it instead of x and y you get y - intercept of -5.

Hope this helps. Pls give brainliest.

4 0
3 years ago
How do yo work out 9.1 divided by 3575
EastWind [94]
9.1/3575
use long division like this
         _<u>0.</u>_________
3575|91.000000

we find how many of 3575 fit into the 91
it's too big so we go farther
how many 3575 go into 910
too big so we go farther
how many 3575 go into 9100
the answer is 2 so put that in the correct place and mulitply that and put that in the correct place. then we subtract

         _<u>0.</u><u>02</u>_________
3575|91.000000
        -<u>71.50</u>
         19.50
bring down the next number
find how many go into 19.500
the answe ris 5


         _<u>0.</u><u>02</u><u>5</u>_________
3575|91.000000
        -<u>71.50</u>
         19.500
        -<u>17.875</u>
           1.625
          
bring down he next zero ( I fast forward and skip steps for convinience)

                      __
         _<u>0.</u><u>02</u><u>5</u><u>455</u>_________
3575|91.000000
        -<u>71.50</u>
         19.500
        -<u>17.875</u>
           1.6250
          -<u>1.4300</u>
             .19500
            -<u>.17875
</u>                16250
               -14300
and so on untill infinity so the answe ris 0.0254555555555555 (enless fives)
8 0
3 years ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}

\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

5 0
2 years ago
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