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eduard
3 years ago
9

Rewrite the expression as a sum of terms, where each term is in the form k\cdot a^nk⋅a

Mathematics
1 answer:
muminat3 years ago
8 0

Answer:

  2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}

Step-by-step explanation:

It looks like you want to expand the expression ...

  \sqrt{a}\left(2a^2 -\dfrac{4}{a}\right)

Use the distributive property and rules of exponents.

  =2a^{(\frac{1}{2}+2)}-4a^{(\frac{1}{2}-1)}\\\\=\boxed{2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}}

_____

The relevant rules of exponents are ...

  √a = a^(1/2)

  1/a = a^-1

  (a^b)(a^c) = a^(b+c)

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Find an expression which represents the sum of (3x+2)(3x+2) and (6x-10)(6x−10) in simplest terms.
ArbitrLikvidat [17]

Step-by-step explanation:

sum means add

(3x+2)(3x+2) = 6x+4

4 0
2 years ago
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How many 12 inch rulers will be about the same length as a bike
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Assuming the bike is 70 inches

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3 years ago
6) (after 2.3) Consider the infinite system of linear equations in two variables given by ax + by = 0 where (a, b) moves along t
Paraphin [41]

Answer:

Step-by-step explanation:

Given infinite system of linear equations is ax + by = 0

when (a,b) moves along unit circle in plane.

a) system having unique system (0, 0)

Since two of equation in thus system will be

1.x+0.y=0\\x=0

and

0.x+1.y=0\\y=0

It is clear that x = 0, y= 0 is the only solution

b) Linear independent solution in this system gives some set of solutions

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and

0.x+1.y=0\\y=0

Vector form is

\left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =I

c) for this equation if add 0x +0y = 0 to system , Nothing will change

Because [0,0] satisfies that equation

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6 0
3 years ago
Help meeeeedkxkdjsjs
Alex
18 - (8 - 3 • (2t + 5)) = 0



6t + 25 = 0



3.1 Solve : 6t+25 = 0

Subtract 25 from both sides of the equation :
6t = -25
Divide both sides of the equation by 6:
t = -25/6 = -4.167

Final answer is

t = -25/6 = -4.167
5 0
3 years ago
Prime between number of 1234 to 1352​
qwelly [4]

prime between number of 1234 to 1352​ are 1237, 1249,  1259, 1277, 1279, 1283, 1289, 1291, 1297, 1301, 1303, 1307, 1319, 1321, 1327

8 0
2 years ago
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