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eduard
3 years ago
9

Rewrite the expression as a sum of terms, where each term is in the form k\cdot a^nk⋅a

Mathematics
1 answer:
muminat3 years ago
8 0

Answer:

  2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}

Step-by-step explanation:

It looks like you want to expand the expression ...

  \sqrt{a}\left(2a^2 -\dfrac{4}{a}\right)

Use the distributive property and rules of exponents.

  =2a^{(\frac{1}{2}+2)}-4a^{(\frac{1}{2}-1)}\\\\=\boxed{2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}}

_____

The relevant rules of exponents are ...

  √a = a^(1/2)

  1/a = a^-1

  (a^b)(a^c) = a^(b+c)

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The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
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(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

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Step-by-step explanation:

(a) Male expenditure

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Sample mean= $68.64, sd=$20, n=30, Z=2.576

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(b) Male: Error margin = (t-value × sd)/√n

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CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

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3 years ago
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