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3 years ago

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3 equivalent fractions for 9/7

1 answer:

yawa3891 [41]3 years ago

5 0

To find three equivalent fractions of a fraction, simply multiply the fraction by a common factor.

For example, multiple both the numerator and denominator of 9/7 by 2.
This will give you a fraction of 18/14, which is equivalent.

You can do this with any number you like to create three equivalent fractions.

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Suppose that $9500 is placed in an account that pays 8% interest compounded each year.

Blababa [14]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}$

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2 years ago

Suppose that the breaking strength of a rope (in pounds) is normally distributed, with a mean of 100 pounds and a standard devia

EleoNora [17]

Answer:

0.961

Step-by-step explanation:

To answer this, find the area under the standard normal curve to the left of 130 pounds:

Using the function normalcdf( on a TI calculator, we get:

normalcdf(-1000, 130, 100, 17) = 0.961

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2 years ago

the number of students in the four sixth-grade classs at northside school are 26, 19,34 and 21. Use properties to find the total

Aleks04 [339]

In this case all you do is add all the numbers, answer is 100

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3 years ago

The capacity of an elevator is 12 people or 2088 pounds. the capacity will be exceeded if 12 people have weights with a mean gre

boyakko [2]

suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?

Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Mean = 177

standard deviation = 26

We find z-score using given mean and standard deviation

z = $\frac{x-mean}{standard deviation}$

= $\frac{174-177}{26}$

=-0.11538

Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)

= 0.5438

P(weight will be greater than 174 lb) = 0.5438

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3 years ago

How do you solve 8y=48 one step equation

ValentinkaMS [17]

Divide each side by 8

y=6

8 0

3 years ago

Read 2 more answers