If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)

5 0

2 years ago

PLEASE HELP ASAP<br> I'LL MARK BRAINIEST

IRINA_888 [86]

Answer:

A. 2.35

Step-by-step explanation:

8 0

1 year ago

Find the area of a triangle with a base length of 3 units and a height of 4 units.

svetlana [45]

Answer:

$6$ square units

Step-by-step explanation:

The area of a triangle can be calculated by multiplying the triangle's base by its height, and then dividing the result by $2$ . As an algebraic expression, this would be $\frac{bh}{2}$ , where $b$ is the triangle's base and $h$ is the triangle's height. In this case, we know that $b=3$ and $h=4$ . Therefore, the area of this triangle is $\frac{3*4}{2} =\frac{12}{2} =6$ square units. Hope this helps!

6 0

2 years ago

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