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klemol [59]
3 years ago
8

A train is booked to do the run between two places 55 km apart,in 1 hr 20 min. if it travels for the first 30 km at 36km per hou

r, at what speed must it travel for the rest of the distance in order to complete the journey in time​
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
6 0

Answer:

<em>The train must travel at 50 km/hr to make it on time.</em>

<em></em>

Step-by-step explanation:

distance to be covered = 55 km

time to cover this distance = 1 hr 20 min

1 hr 20 min = 1.33 hrs (20 min = 20/60 hrs = 0.33 hrs)

The train travels the first 30 km distance at a speed of 36 km/hr

and we know that time taken = distance/speed

therefore the time taken to run this 30 km will be

time = 30/36 = 0.83 hr

The train still has 55 - 30 = 25 km to cover,

and the time left is 1.33 - 0.83 = 0.5 hrs left

to make it on time, the train must travel at

speed = distance/time = 25/0.5 = <em>50 km/hr</em>

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Tia is traveling from city A to city B. The two cities are 320 miles apart. She has traveled 260 miles at a steady speed for 4 h
allochka39001 [22]

Answer:

65mph

Step-by-step explanation:

forget about how far apart the cities are for now instead divide 260/4 because tia has traveled 260M for 4 hours

distance

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  time

260/4=65

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The length of a photograph is 3cm less than twice the width. The area is 54cm². Find the dimentions of the photograph.
AnnyKZ [126]
L=2w-3 

w(2w-3)=54

2w²- 3w-54=0

A= 2 , B= -3, C= -54

sub values into quadratic formula
 i attached picture of formula

Final answer:  you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.

w=6

Check:
L=2w-3
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Therefore the dimensions of the photograph are 6 cm by 9 cm



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A local police chief claims that 31% of all drug-related arrests are never prosecuted. A sample of 500 arrests shows that 27% of
Elis [28]

Answer:

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X represent the number of arrests that were not prosecuted.

\hat p=0.27 estimated proportion of arrests that were not prosecuted

p_o=0.31 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.31.:  

Null hypothesis:p\geq 0.31  

Alternative hypothesis:p < 0.31  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

3 0
3 years ago
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