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3 years ago

Expand the exppresion -7(k-3)

Mathematics

2 answers:

Lana71 [14]3 years ago

8 0

Answer:

-7k+21

Step-by-step explanation:

Tanya [424]3 years ago

3 0

Answer:

-7k +21

Step-by-step explanation:

-7(k-3)

Distribute

-7*k -7*(-3)

-7k +21

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6k ÷ 7 = -3<br> Solve for k

fomenos

Answer:

k = -3.5

Step-by-step explanation:

6k ÷ 7 = -3

Multiply 7 to both sides

6k = -21

Divide both sides by 6

6k/6 = -21/6

k = -3.5

To check if the answer is correct or not, you can always plug in -3.5 for k in the equation.

6(-3.5) ÷ 7 = -3

-21 ÷ 7 = -3

-3 = -3

-3 equals -3 so it is correct that k = -3.5

4 0

3 years ago

Simplify 7^-5/6*7^-7/6

DochEvi [55]

So the rule with multiplying exponents of the same base is $x^m*x^n=x^{m+n}$ . Apply this rule here:

$7^{-\frac{5}{6}}*7^{-\frac{7}{6}}=7^{-\frac{5}{6}+{-\frac{7}{6}}}=7^{-\frac{12}{6}}=7^{-2}$

Next, the rule with converting negative exponents into positive ones is $x^{-m}=\frac{1}{x^m}$ . Apply this rule here:

$7^{-2}=\frac{1}{7^2}=\frac{1}{49}$

<u>Your final answer is 1/49.</u>

So an additional rule when it comes to exponents is $x^{\frac{m}{n}}=\sqrt[n]{x^m}$

In this case, your fractional exponent, x^9/7, would be converted to $\sqrt[7]{x^9}$ . However, I had just realized you can further expand this.

Remember the rule I had mentioned earlier about multiplying exponents of the same base? Well, you can apply it here:

$\sqrt[7]{x^9}=\sqrt[7]{x^7*x^2}=x\sqrt[7]{x^2}$

Your final answer would be $x\sqrt[7]{x^2}$

3 0

3 years ago

Describe the transformation of the graph of the parent function y= sqrt x+7 + 5

stellarik [79]

Answer:

The function moves 7 to the left and 5 units up

Step-by-step explanation:

y = (x + 7) + 5

I think that's the problem you put.

8 0

3 years ago

Read 2 more answers

Gary applied the distributive property using the greatest common factor to determine the expression that is equivalent to 66+36.

mestny [16]

Answer:

6(11+6)

Step-by-step explanation:

Greatest common factor of 66 and 36 = 6

66+36 = 6*11 + 6*6 = 6(11+6)

5 0

3 years ago

I need help with this, neither of my parents can help me and i want to understand.

olga2289 [7]

Answer:

See explanation

Step-by-step explanation:

1. To rewrite the expression

$(4^{\frac{2}{5}})^{\frac{1}{4}},$

use exponents property

$(a^m)^n=a^{m\cdot n}$

So,

$(4^{\frac{2}{5}})^{\frac{1}{4}}=4^{\frac{2}{5}\cdot \frac{1}{4}}=4^{\frac{2}{20}}=4^{\frac{1}{10}}$

2. Why $10^{\frac{1}{3}}=\sqrt[3]{10}?$

Raise both sides to 10 power:

$(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10$

So,

$(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3$

3. Simplify $\dfrac{3^4}{9}$

Use the Quotient of Powers Property:

$\dfrac{a^m}{a^n}=a^{m-n}$

Then

$\dfrac{3^4}{9}=\dfrac{3^4}{3^2}=3^{4-2}=3^2$

4. Solve $4\sqrt{2}+5\sqrt{4}$

First, note that $\sqrt{4}=2,$ then

$4\sqrt{2}+5\sqrt{4}=4\sqrt{2}+5\cdot 2=4\sqrt{2}+10$

Number $4\sqrt{2}$ is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.

5. The same as option 4.

3 0

3 years ago