The ball hits the ground when the height h(t) = 0 , so
-16t^2 + 80t = 0
-16t(t - 5) = 0
t- 5 = 0 or -16t^2 = 0 ( here t = 0 which corresponds to when ball is thrown)
t - 5 = 0 gives:-
t = 5 seconds (answer)
Answer:
Step-by-step explanation:
I have to go with 9r-18= -27 is my answer for your math
Answer:
5x + 4y + 12 = 0
Step-by-step explanation:
Start with the point-slope equation of a straight line: y - k = m(x - h):
Here we are given the point (h, k): (-8, 7) and the slope m = -5/4. Inserting this info into the equation give above, we get: y - 7 = (-5/4)(x + 8).
We must put this equation into "standard form" Ax + By + C = 0.
Multiply all three terms by 4 to remove fractions: 4y - 28 = -5(x + 8), or
4y - 28 + 5x + 40 = 0
Rearranging these terms, we get 5x + 4y + 12 = 0, which is the desired equation in standard form.
Answer:
2x² + 7x + 6
Step-by-step explanation:
To solve this polynomial, you need to distribute/multiply, (x+2) with (2x+3).
You would first multiply (x) with 2x and 3. This would give you 2x² and 3x. You would then multiply 2 with 2x and 3. This would give you 4x and 6. You then add the like-terms, which are 3x and 4x, which gives you 7x. This would give you your final expression of 2x² +7x + 6.
(x+2)(2x+3)
2x²+ 3x + 4x + 6
2x² +7x + 6