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3 years ago

What would this One be??

Mathematics

2 answers:

inn [45]3 years ago

8 0

Answer:

the pre-image and the image are congruent

Step-by-step explanation:

s2008m [1.1K]3 years ago

8 0

Answer:

i think its c

Step-by-step explanation:

You might be interested in

Twenty-eight slices of pizza cost $12. Approximately how much would 70 slices cost?

Mademuasel [1]

Answer:

$30.

Step-by-step explanation:

70/28 = 2.5

12 x 2.5 = 30

5 0

2 years ago

At a computer store, a customer is considering 9 different computers,10 different monitors,8 different printers and 2different s

Leto [7]

Answer:

The number of different computer systems possible is 1440.

Step-by-step explanation:

For each computer, there are 10 options of monitor.

For each monitor, there are 8 printers.

For each printer, there are 2 scanners.

There are 9 computers.

Determine the number of different computer systems possible.

9*10*8*2 = 1440

The number of different computer systems possible is 1440.

3 0

3 years ago

Hi my question is what is 72x13

wariber [46]

936 is the answer :)))))))))))

4 0

3 years ago

Read 2 more answers

How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

5 0

3 years ago

PLEASE HELP ME YOU GET IT RIGHT I WILL MARK BRAINLIST but if its wrong... i report you

mamaluj [8]

I’m pretty sure it’s 60 but I’m not 100% sure so I’m sorry if it’s wrong

6 0

2 years ago