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emmasim [6.3K]
3 years ago
6

I need help!!

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer:

1st is valid 2nd is not valid

Step-by-step explanation:

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Understanding tens and ones
Semenov [28]
The number 15 has 2 place values.
 
The value in the tens place is 1. 
The value in the ones place is 5.

1 tens + 5 ones = 15

If you need help comment below and ill try my best to help you out!
4 0
3 years ago
Read 2 more answers
there are 1024 players in a tennis tournament in each round half of the players are eliminated which function can be used to fin
jonny [76]

Answer: f(x) = 1,024(0.50)^x

Step-by-step explanation:

Hi, to answer this question we have to apply a decreasing rate formula:

f(x)= P (1 - r) ^x

Where:  

p = original number of players

r = decreasing rate (decimal form, since half of the players are eliminated the percent decrease is 50%)

x = rounds  

f(x) = number of players after x rounds

Replacing with the values given:

f(x) = 1,024(1-50/100)^x

f(x) = 1,024(1-0.5)^x

f(x) = 1,024(0.5)^x

7 0
3 years ago
Can you answer this
Burka [1]
Answer is 2x^+3x-3 with reminder 4
6 0
3 years ago
Solve systems of three variable equations - how to do :(​
krek1111 [17]

a= 6-2b-3c

then put that equation inside the first one and then the second one

you get -6*(6-2b-3c)+2b-3c=23

and 5*(6-2b-3c)+4b-3c=-12

14b-15c=59

14b-18c=18/*(-1)

--------------------

3b=41

7 0
3 years ago
Eva payrolls for on a number cube and the number of cubes roll 24 times then what is a reasonable prediction for the number of s
Allushta [10]

Answer:

The reasonable prediction for successful rolls is 4.

Step-by-step explanation:

Assuming the rolling cube  is a fair 6 sided cube, so the probability of success of one roll is given as

P(Success)=\dfrac{Number\ of\ successful\ events}{Number\ of\ total\ events}

P(Success)=\dfrac{1}{6}

The total success is given as

P(Total\ Success)=P(Success)\times Number\ of\ events

For 24 rolls it is given as

P(Total\ Success)=P(Success)\times Number\ of\ events\\P(Total\ Success)=\dfrac{1}{6}\times 24\\P(Total\ Success)=4

So the reasonable prediction for successful rolls is 4.

3 0
3 years ago
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