area of triangle = 1/2(3)(4) = 6 in^2
area of rectangle = 3 x 10 = 30 in^2
area of trapezoid = 1/2(3+5)(2) = 8 in^2
area of the figure: 6 in^2 + 30 in^2 + 8 in^2 = 44 in^2
answer
44 in^2
I need to find the mean, median,mode, and range of 8,6,7,6,5,4 1/2, 7 1/2, 6 1/2, 8 1/2, 10,7,5, 5 1/2, 8,9, 7,5,6, 8 1/2, and 6
sattari [20]
Answer:
add them all up and divide by 19
Step-by-step explanation:
Answer:
a) C(x) = 15000/x + 6x +80
b) Domain of C(x) { R x>0 }
Step-by-step explanation:
We have:
Enclosed area = 1500 ft² = x*y from which y = 1500 / x (a) where x is perpendicular to the river
Cost = cost of sides of fenced area perpendicular to the river + cost of side parallel to river + cost of 4 post then
Cost = 10*y + 2*3*x + 4*20 and accoding to (a) y = 1500/x
Then
C(x) = 10* ( 1500/x ) + 6*x + 80
C(x) = 15000/x + 6x +80
Domain of C(x) { R x>0 }
