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3 years ago

In the equation y = 39x + 50represents the number of people at a holiday dinner and y represents the total cost of

Mathematics

1 answer:

kkurt [141]3 years ago

6 0

Answer:

The correct answer is - 12.

Step-by-step explanation:

Given:

Total number of people = y = 39x+50

Total amount spent y = 518

Solution:

The equation for the number of people who attended the dinner

y = 39x+50

The cost of dinner is equally divided by number of people =

then, 518 = y

placing value, 518 = 39x+50

x = (518-50)/39

= 468/39

= 12

Then number of people attended the dinner = 12

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A team from each school had 250 foam balls and a bucket. The Jackson team dunked 6 fewer balls than the Pine Street team. The Pi

lara [203]

478 because the pine dunked all but 8 so 250-8=242 then Jackson dunked 6 fewer so 242-6=236 then all together 242+236=478

4 0

3 years ago

How would you integrate (2x-1)(6x+5)? is there a product rule for integration?

NikAS [45]

No, there is not a product rule for integration.

To integrate (2x - 1)(6x + 5), start expanding the product:

(2x - 1)(6x + 5) = 12x^2 + 10x - 6x - 5 = 12x^2 + 4x - 5.

Now, I guess you know how to integrate that:

∫ (12x^2 + 4x - 5) dx = ∫12x^2 dx + ∫4x dx + ∫ (-5) dx = 4x^3 + 2x^2 - 5x + C

4 0

4 years ago

A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban

zalisa [80]

Answer:

4212 : 1573 is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be $x.$

As, sign is similar to banner.

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to $x.$

$\frac{36}{52} =\frac{22}{x}$

By cross multiplying we get:

$36x=1144$

Dividing both sides by 36 we get:

$x=31\frac{7}{9} .$

Hence, the width of sign is $31\frac{7}{9}$ inches.

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

$Area\ of\ banner=36\times 52$

$Area\ of\ banner=1872\ square\ inches.$

Now, area of sign:

$Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.$

Now, to get the ratio of the area of the school banner to the area of the sign:

$1872:\frac{6292}{9}$

$=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}$

On simplifying we get:

$=\frac{4212}{1573}$

$=4212:1573.$

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

8 0

3 years ago

-4 + x / 2 = 3 urgent!

Zina [86]

$\frac{-4 + x}{2}$ = 3 Multiply both sides by 2
-4 + x = 6 Add 4 to both sides (to cancle out the -4)
x = 10

4 0

3 years ago

T(8,2) is reflected across the x-axis.

skad [1K]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ T (8, 2) reflected across the x-axis is (8, -2). When you reflect over the x-axis, the sign in front of the y coordinate changes. When you reflect over the y-axis, the sign in front of the x coordinate changes.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

6 0

4 years ago