Answer:
Help me please in my question
The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>
From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
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Quadrant 4 is the correct answer, and it's the only
Which one is the length, height, and width? After you that then multiple and you should have your answer. Hope this helps!
Answer:
m=-3
Step-by-step explanation:
Since the lines are parallel to each other, their gradients are equal.
∴ gradient of green line = gradient of red line
∴ m = -3