Answer:
B= 2y(3)/7x(8)
C= 12/ x(3) y(3)
D= The same because nothing else can be done with it
(parnthaces) are exponents
Think of integers that have a sum (addition) of 8 that don't include negative integers.
4+4=8
6+2=8
5+3=8
Pat is right there are three different pairs of integers that can have a sum of 8.
Answer:
How many One-sixths are in Two-thirds?
Step-by-step explanation:
The probability of those sequence of events is 2/21
