Ask question

Ask question

All categories

2 years ago

11

ANSWER FOR BRAINLIEST:

1 answer:

AlekseyPX2 years ago

3 0

Step-by-step explanation:

<em><u>I </u></em><em><u>thin</u></em><em><u>k</u></em><em><u> </u></em><em><u>mode</u></em><em><u>,</u></em><em><u>range</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>median</u></em><em><u> </u></em><em><u>dpo</u></em><em><u> </u></em><em><u>ako</u></em><em><u> </u></em><em><u>sure</u></em>

You might be interested in

Anthony bought an 8 foot board. He cut off 3/4 off the board to build a shelf and gave 1/3 of the rest to his brother for an art

Zina [86]

8 inches. 3/4 of 8 feet is 6 feet leaving two left over, one third of that is 8 inches.

6 0

3 years ago

Read 2 more answers

Please help? Thank you!

Zarrin [17]

The statements that are true are A, B, and D

7 0

3 years ago

The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional

jolli1 [7]

Answer:

x= $\frac{16}{\sqrt[3]{2}+1 }$

Step-by-step explanation:

Q= illumination

I = intensity

Q= I/d^2

Q_total = $\frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}$

= $\frac{I}{x^2}+\frac{2I}{(16-x)^2}$

now Q' = 0

⇒I ${-\frac{2}{x^3}}+\frac{4}{(16-x)^3}$

x= $\frac{16}{\sqrt[3]{2}+1 }$

[/tex] $\frac{1}{x^3} = \frac{2}{(16-x)^3}$

x= $\frac{16}{\sqrt[3]{2}+1 }$

is the required point

5 0

3 years ago

Find the product for the following expressions: <br> (8c + 2)(5c-7)

Marianna [84]

Answer:40c^2-46c -14

Step-by-step explanation:

(8c+2)*(5c-7)

8c*(5c-7)+2(5c-7)

40c^2-56c+10c-14

40c^2-46c-14

8 0

3 years ago

Read 2 more answers

A figure is composed of a rectangle and a right triangle. What is the area of the figure?

strojnjashka [21]

QUESTION 1

The figure is a tra-pezoid.

The area of a trapezoid is given by the formula;

$A=\frac{1}{2}(Sum\:of\:parallel\:sides)\times h$

We substitute the values to obtain;

$Area=\frac{1}{2}(13.2cm+8.4cm)\times 6cm$

$Area=\frac{1}{2}(21.6cm)\times 6cm$

$Area=64.8cm^2$

QUESTION 2

The approximate length of the ribbon is equal to the circumference of the circular table cloth.

We can find this by using the formula for calculating the circumference of a circle.

$C=2\pi r$

where $r=3.5ft$ is the radius of the circular table cloth.

We substitute this value and $\pi=3.14$ into the formula to get;

$C=2(3.14)(3.5)ft$

$C=21.98ft$

The approximate length of the ribbon is 22.0ft to the nearest tenth.

QUESTION 3

Type of quadrilateral:Rectangle

Explanation: A rectangle has 4 angles that are right angles.

The two pairs of opposite sides of a rectangle are also congruent.

QUESTION 4.

The circumference of a semi circle is calculated using the formula;

$C=\pi r$

where $r=12.5cm$ is the radius of the semicircle.

$C=3.14\times 12.5cm$

$C=39.25cm$

QUESTION 5

The area of the entire figure is the area of the semicircle plus the area of the isosceles triangle.

$Area=\frac{1}{2}\pi r^2+\frac{1}{2}bh$

$Area=\frac{1}{2}\times3.14\times12.5^2+\frac{1}{2}\times25\times 24$

$Area=345.3125+300$

$Area=645.3125cm^2$

$Area\approx645cm^2$

QUESTION 6

The area of the parallelogram is given by the formula;

$A=bh$

From the diagram, $b=y\:in.,h=3in.$ .

Given, A=23.7 inches squared.

We substitute the values to obtain;

$23.7=3y$

$y=\frac{23.7}{3}$

$y=7.9in.$

QUESTION 7

The area of a rectangle is given by the formula;

$Area=l\times b$

The area of the bigger rectangle $=9\times15=135in^2$

The area of the smaller rectangle $=8\times 13=104in^2$

The area of the shaded region $=135-104=31in^2$

5 0

3 years ago