The complete question in the attached figure
we know that
m∡4=65°
m∡4=m∡2---------> by internal alternate angles
m∡5=m∡3---------> by internal alternate angles
m∡1=180°-m∡2---------> 180°-65°--------> m∡1=115°
the answer is
m∡1=115°
Answer:
Money raised by each team = 94 + 11 = <em>$105</em>
Number of cars washed = <em>11</em>
Step-by-step explanation:
Money already present with volleyball team = $50
Money raised by washing each car by volleyball team = $5
Let the number of cars washed = 
Money raised by washing cars = $5
Money already present with volleyball team = $94
Money raised by washing each car by volleyball team = $1
Money raised by washing cars = $1 = $
Given that, both the teams have raised same amount of money:
Money raised by each team = 94 + 11 = <em>$105</em>
Number of cars washed = <em>11</em>
Step-by-step explanation:
the number of pupils are in the lower school
= (1- 1/5 - ¼) × 600
= (20/20 - 4/20 - 5/20)×600
= (11/20) ×600
= 330 pupils
Answer:
No parallel lines will never intersect.
Step-by-step explanation:
They go in the same direction almost like an equals sign "="
Answer:
The number of the television sets that is model p is 12
Step-by-step explanation:
Here we have total number of television sold = 40
The model p televisions sold for $30 less than the model q televisions
That is $P = $q - $30
Therefore
Let the quantity of the model p sold be X
Let the quantity of the model q sold be X
Therefore
x + y = 40
Total cost of the television = 40 * 141 = $5640
Therefore, 120*x + 90*y = 5640
Plugging in x = 40 - y in the above equation we get
4800 - 30y = 5640 or
y = -28 and
x = 68
If we put y = 40 - x we get
30x + 3600 = 5640
If we put
120*x + 150*y = 5640.........(3)
we get
x = 12 and y = 28
Therefore, since the model p sold for $30 less than the model q, from the solution of equation (3) the number of the television sets that is model p = 12
