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horrorfan [7]
3 years ago
9

Which algebraic expression is equivalent to the expression below?

Mathematics
2 answers:
Sindrei [870]3 years ago
7 0

Answer:

the answer is 29x + 72, none of the following options does not have the answer

Alenkasestr [34]3 years ago
3 0

Answer:

A. 26x + 72

Step-by-step explanation:

  1. 5(6x + 8) + 4(8 - x) = 5 * (6x + 8) + 4 * (8 - x)
  2. 5 * (6x + 8) + 4 * (8 - x) = (5*6x + 5*8) + (4*8 -4*x)
  3. (5*6x + 5*8) + (4*8 - 4*x) = (30x+40) + (32 - 4x)
  4. (30x+40) + (32 - 4x) = 30x+40 + 32 - 4x
  5. 30x+40 + 32 - 4x = (30x - 4x) + (40 + 32)
  6. 26x + 725 * (6x + 8) + 4 * (8 - x)5 * (6x + 8) + 4 * (8 - x)5 * (6x + 8) + 4 * (8 - x)5 * (6x + 8) + 4 * (8 - x)
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A soccer ball manufacturer wants to estimate the mean circumference of soccer balls within 0.1 in. Determine the minimum sample
leva [86]

Answer:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)  

\sigma=0.25 represent the population standard deviation

n represent the sample size (variable of interest)  

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}  

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =0.1 and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

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Step-by-step explanation:

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What is 4.25 round to one decimal place
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Rounded to one decimal place means to round to the nearest tenth (i.e. to the nearest 0.1)

4.25 (rounded to the nearest tenth) = <u><em>4.3</em></u>
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Read 2 more answers
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