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tino4ka555 [31]
2 years ago
10

Help plz will give brainliest

Mathematics
2 answers:
sergey [27]2 years ago
6 0

5 x 3 = 15

Your answer: 15

sineoko [7]2 years ago
3 0

Answer: 15 out of the 18 blocks are shaded

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1. Is the square root of 2 between 1.3 and 1.4? How do you know?
VikaD [51]

Answer:

Step-by-step explanation:

1st . 1.3^2= 1.69

1.4^2= 1.96

It's not bettween 1.3 & 1.4

2. 1.4^2=1.96

1.5^2= 2.25

it's betteen 1.4 & 1.5

3 . 1.4 & 1.5 so it's eqaul 1.4

3 0
2 years ago
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There are 52 weeks in a year. The plant runs for 12 months. How many weeks let when 52 weeks are divided by 12 months?​
xxMikexx [17]

Step-by-step explanation:

in one month , it runs for 52/12 weeks

that is 4 weeks

3 0
2 years ago
Can someone please help me with this and show work as well?? thank you so much!
Schach [20]
Use a compass to make a circle around both lasers at the same degree and they should over lap. where they over lap use your straight edge to make a direct line from the point where your at through where they cross. that will be your answer, hope i helped.
8 0
3 years ago
Stephen uses \dfrac{2}{25}
zepelin [54]

Answer:

13\dfrac{3}{4}$ servings

Step-by-step explanation:

Stephen uses \dfrac{2}{25} kilograms of tofu in each serving of his dish.

He has 1\dfrac{1}{10} kilograms of tofu.

We want to determine how many servings Stephen can make.

To do this, we divide the total weight of tofu by the weight per serving.

\dfrac{\text{Total Weight(in kg)}}{\text{Weight(kg) per serving}} =\dfrac{1\dfrac{1}{10}}{ \dfrac{2}{25}}\\ = \dfrac{11}{10}\div  \dfrac{2}{25}\\\\= \dfrac{11}{10}X  \dfrac{25}{2}\\\\= \dfrac{11X25}{10X2}\\\\= \dfrac{275}{20}\\\\=13\dfrac{3}{4}$ servings

Stephen can make 13\dfrac{3}{4}$ servings .

6 0
3 years ago
Which number produces a rational number when added to 0.3?
Afina-wow [57]

Basically you need to find the answer choice that is rational. That way the sum will also be rational.

√7 is irrational as well as π and 0.5050050005...

2/4 is the only rational option.

answer: D

6 0
3 years ago
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