Answer:
x=45°
Step-by-step explanation:
The 160° plus the unlabeled angle to the left of it are supplementary, meaning when added they equal 180°. The unlabeled angle will therefore be 20°. The angle across from the 20° will also be 20°. 115° + 20° = 135°. Now all that is left on the top half is x.
180° - 135° = 45°
Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
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9514 1404 393
Answer:
(b) 48
Step-by-step explanation:
In this geometry, the altitude (x) is the root of the product of the segments of the hypotenuse.
x = √(36·64) = √36×√64 = 6×8
x = 48
_____
All of the triangles are similar, so the ratios of corresponding sides are the same.
short side/long side = x/64 = 36/x
x^2 = (64)(36) . . . . as above
F=21 (A)
I hope this was helpful
