Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
160
Step-by-step explanation:
e.g. 5×8 --> 10×16 =160
4×10 --> 8×20 =160
2×20 --> 4×40 =160
Answer:
true
Step-by-step explanation:
Answer:
d. does not exist
Step-by-step explanation:
The given limits are;
, 
and 
We want to find
By the properties of limits, we have;
This gives us;
Division by zero is not possible. Therefore the limit does not exist.
Answer:
B. 9x10^4
Step-by-step explanation:
