Answer:
The answer is weak, Have a nice day! :)
Explanation:
D) weak
Answer:
In Python:
import os.path
from os import path
fname = input("Filename: ")
if path.exists(fname):
with open(fname) as file_in:
lines = []
for line in file_in:
lines.append(line.rstrip('\n'))
f = open("stat.txt","r+")
f.truncate(0)
f = open("stat.txt", "a")
f.write("Names\tTotal\tSubjects\tAverage\n")
for i in range(len(lines)):
rowsum = 0; count = 0
nm = lines[i].split()
for j in nm:
if (j.isdecimal()):
count+=1
rowsum+=int(j)
average = rowsum/count
f.write(nm[0]+"\t %3d\t %2d\t\t %.2f\n" % (rowsum, count, average))
f.close()
else:
print("File does not exist")
Explanation:
See attachment for explanation where comments were used to explain each line
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
A password and pin hope this helps :D
