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NemiM [27]
3 years ago
5

Samuel wanted to paste the value and the formula attached from cell B6 to cell F16. Which methods will work? Check all that appl

y.
Computers and Technology
2 answers:
Stells [14]3 years ago
3 0

Answer:

Select cell B6, copy, and paste special into F16.

Select cell B6, Ctrl+C, and Ctrl+V into F16.

Select cell B6, copy, and paste into F16.

Explanation:

got it right on edge.

tatiyna3 years ago
3 0

Answer:b,c,e

Explanation:

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A Unit of information containing the objects position, rotation, and scale values is called:
Paraphin [41]

The answer is:

B) A transform.



5 0
3 years ago
​ In addition to analyzing logic and program code, a project team usually holds a session with users, called a _____, to review
andreev551 [17]

Answer:

design walk-through

Explanation:

In addition to analyzing logic and program code, a project team usually holds a session with users, called a <u>design walk-through</u>, to review the interface with a cross-section of people who will work with the new system and ensure that all the necessary features have been included.

A design walk-through is a quality practice that allows designers to obtain an early validation of design decisions related to the development and treatment of content, design of the graphical user interface, and the elements of product functionality.

8 0
3 years ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
Why would it be unusual to find a fossil of an organism’s eye?
Slav-nsk [51]
<span>The preservation of anything other than mineral skeletons is (with a few exceptions described below) an extremely rare event. Anything that can decay is likely to be lost. Fur, skin, internal organs – all are immensely vulnerable to the destruction by bacteria, fungi and scavengers that assure their recycling back into the ecosystem. </span>
8 0
3 years ago
Question 3 (2 points)
jeyben [28]

Answer:

The energy source that does not use heat in the process of converting it to electricity is;

c. Sunlight

Explanation:

In converting Sunlight energy source to electricity, the photons in the light from the Sun excite electrons in the solar cells silicon layers, such that the electrons travel from n-type silicon layer to the p-type silicon layer creating electric potential energy that does work as the electrons flow back in the form of electricity from the p-type to the n-type silicon layer through an external circuit

7 0
3 years ago
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