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nikdorinn [45]
2 years ago
13

PLEASE HELPPPPP..........!!!

Mathematics
1 answer:
alisha [4.7K]2 years ago
7 0
I can’t see it well...like it’s blurring
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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
prohojiy [21]

Answer:

2.25

Step-by-step explanation:

(6x^{-2})^2(0.5x)^4\\\\=(6^2(x^{-2})^{2})(0.5^4x^4)\ \ \ \ \ \ \ \ \ \ \ \ \ as\ (ab)^m=a^mb^m\\\\=36\times 0.5^4((x^{-2})^2x^4)\ \ \ \ \ \ \ \ \ \ as\ multiplication\ is\ associative\ a(bc)=(ab)c\\\\=36\times 0.0625(x^{-4}x^4)\ \ \ \ \ \ \ \ \ \ \ as\ (x^m)^n=x^{mn}\\\\=(36\times 0.0625)(x^{-4+4})\ \ \ \ \ \ \ \ \ \ \ as\ x^mx^n=x^{m+n}\\\\=2.25x^0\\\\=2.25\ \ \ \ \ \ \ \ \ \ \ \ as\ x^0=1\\\\(6x^{-2})^2(0.5x)^4=2.25

7 0
3 years ago
Will mark brainiest!!!
romanna [79]

B

Happy to help :)

Have a great day:)

3 0
3 years ago
5÷5+6÷6÷6÷6÷6÷6÷6÷6÷6÷6×6×7+7+8+9+3+5*6*6
Reil [10]

Answer:

208.00015

Step-by-step explanation:

Use a calculator. I'm sorry, there's no other way

4 0
3 years ago
Read 2 more answers
If two zeroes of the polynomial x4-6x3-26x2+138x-35 are x+3 and x-3. Find the other zeroes
ASHA 777 [7]

Answ

Step-by-step explanation:

5 0
3 years ago
Help<br> help please please
Ahat [919]

Answer:

1. A

2. C

Step-by-step explanation:

I could be wrong, that's my best guess. Im so sorry if im wrong, have a good day

7 0
3 years ago
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