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2 years ago

Is this correct if not can someone give me the answer I will mark u brilliant

Mathematics

2 answers:

Mila [183]2 years ago

4 0

Answer: the first one is 735.75

the second one is 69

Step-by-step explanation:

THEY ARE BOTH CORRECT!

Oduvanchick [21]2 years ago

3 0

Answer: They are both correct. Good job! :)

Step-by-step explanation:

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Please answer this correctly without making mistakes I want ace expert and genius people to answer this correctly without making

sergejj [24]

Answer: 38

Step-by-step explanation: to evaluate an expression for these variables, plug in those numbers for the variables.

Plugging in -1 for y and -19 for z gets you this:

-2(-1)^2(-19)

Now simplify according to order of operations (PEMDAS - parenthesis exponents multiplication/division addition/subtraction)

-1^2 = 1

-2(1) = -2

-2(-19) = 38

Your answer is 38

7 0

2 years ago

What is the decimal equivalent for 1 5/27

grandymaker [24]

Answer: 1.18519

Step-by-step explanation:

1 5/27 = 32/27

= approximate value = 1.18519

5 0

2 years ago

(8,-3) and (8,4) Linear functions

lesya692 [45]

Answer:

$\displaystyle x = 8$

Step-by-step explanation:

Anything set to equal x is considered an undefined rate of change [slope], which is a vertical line. This is not a function, since it flunks the vertical line test.

I am joyous to assist you anytime.

4 0

2 years ago

The volume of a cone of radius r and height h is given by V=πr²h³. If the radius and the height both increase at a constant rate

Aloiza [94]

Answer:

The volume of cone is increasing at a rate 1808.64 cubic cm per second.

Step-by-step explanation:

We are given the following in the question:

$\dfrac{dr}{dt} = 12\text{ cm per sec}\\\\\dfrac{dh}{dt} = 12\text{ cm per sec}$

Volume of cone =

$V = \dfrac{1}{3}\pi r^2 h$

where r is the radius and h is the height of the cone.

Instant height = 9 cm

Instant radius = 6 cm

Rate of change of volume =

$\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{1}{3}\pi r^2 h)\\\\\dfrac{dV}{dt} = \dfrac{\pi}{3}(2r\dfrac{dr}{dt}h + r^2\dfrac{dh}{dt})$

Putting values, we get,

$\dfrac{dV}{dt} = \dfrac{\pi}{3}(2(6)(12)(9) + (6)^2(12))\\\\\dfrac{dV}{dt} =1808.64\text{ cubic cm per second}$

Thus, the volume of cone is increasing at a rate 1808.64 cubic cm per second.

5 0

2 years ago

Which table shows a linear function

natka813 [3]

I think it’s the second one but I’m not 100%

6 0

2 years ago

Read 2 more answers