Today, more carbon is located…

I forgot all of this! Please help out!!

e-lub [12.9K]

The answer is a^mn, hope this helped

6 0

2 years ago

Read 2 more answers

Brainliest if answered correctly.

allochka39001 [22]

Answer:

a=35°, b=55°, c=110°

Step-by-step explanation:

reason for a and b is that when 2 lines intersect, the opposite angles are equal.

well for c angles on a straight line add upto 180.

6 0

3 years ago

Let A = {x : 2x² + 3x - 2 = 0} and B = {x : x² + 3x - 4 = 0 } find (A U B) × (A Π B)

ivann1987 [24]

Given :

A = {x: 2x² + 3x - 2 = 0 }
B = {x : x² + 3x - 4 = 0 }

To find :

(A U B ) × (A Π B )

Solution :-

The first set is ,

A ={x : 2x² + 3x - 2 = 0}

Solving the Quadratic equation ,

2x² + 3x - 2 = 0
2x² + 4x - x - 2 = 0
2x( x + 2) -1( x + 2 ) = 0
(2x -1) ( x + 2) = 0
x = 0.5 , -2

Hence ,

A ={0.5, -2}

The second set is ,

B ={ x :x² + 3x - 4 = 0 }

Solving the Quadratic equation ,

x² + 3x - 4 = 0
x² + 4x - x - 4 = 0
x( x + 4)-1 ( x +4) = 0
(x + 4) ( x -1) = 0
x = 1 , -4

Hence ,

B ={1,4}

Now ,

A U B = { 0.5 , 1 , 4 , -2}
A Π B = {∅ }

Since AΠ B is a null set , hence ,

A × B = {∅}

8 0

3 years ago

What’s the answer, and how do I find it step-by-step?

pshichka [43]

Answer: 16p^8q^4r^8 The yellow one

Step-by-step explanation:

Step 1: Use Multiplication Distributive Property: (xy)^a = x^a y^a. So 4^2p^2(q^3)(r^4)^2

Step 2: Simplify 4^2 to 16. So 16p^2(q^3)^2(r^4)^2

Step 3: Use Power Rule: (x^a)^b=x^ab. So 16p^2q^6(r^4)^2

Step 4: Use Power Rule: (x^a)^b=x^ab. So the answer is 16p^2q^6r^8. The yellow one

4 0

3 years ago

In the figure below, points M, P, H, J, and K lie in plane Z.

marishachu [46]

Answers:

(a) LN
(b) PHJ
(c) K
(d) HK

===================================================

Explanation:

Part (a)

Lines LN and PN have the point N in common. This is the intersection point.

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Part (b)

To name a plane, pick any three non-collinear points that are inside it. We cannot pick points H, J, K together because infinitely many planes pass through it. Imagine the piece of flat paper able to rotate around this axis (like a propeller). Having the points not all on the same line guarantees we form exactly one unique plane.

I'll pick the non-collinear points P, H and J to get the name Plane PHJ. Other answers are possible.

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Part (c)

Points H, J and K are collinear as they are on the same line. Pick either H or K to fill out the answer box. I'll go with point K

------------------

Part (d)

Point P and line HK are coplanar. They exist in the same flat plane, or on the same sheet of flat paper together.

We can think of that flat plane as the ground level while something like point N is underground somewhere. So point N and anything on that ground plane wouldn't be coplanar.

Note: there are other possible names for line HK such as line JH or line JK. The order doesn't matter when it comes to naming lines.

4 0

3 years ago