A rectangle has a length of 18 cm and a width of 12 cm. Which length and width would not be those of a similar rectangle?
2 answers:
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Answer:
50 minutes
Step-by-step explanation:
Use proportions
=
Solve for x
3x = 150
Divide by 3
x = 50 minutes
Answer:
29 cans
Step-by-step explanation:
To solve this problem we must use Heron's formula; A =
S = 1/2 the perimeter of the given triangle
a, b, c = the measurements of the three given sides
The first step to solving this question is first finding the perimeter.
P = 65m + 74m + 67m
P = 206m
Now that we have our perimeter, we must divide P by 2 to get S.
S = 206/2
S = 103
Now we plug our numbers into Heron's formula.
A =
A =
A =
A =
A =
Find the square root of this number.
A ≈ 2021.43909134... m²
If a can of paint covers 70 square meters, then you will need to figure out how many cans you need. This can be done by dividing the overall area of the triangle by the area that a single can of paint can cover.
= 28.8777013049...
We know we can't buy 28.87... of a can (people simply do not sell parts of cans or half-full containers... unless its a bag of lays chips and their 80% air nonsense...) so we must round up to the nearest whole number.
28.87... = 29
Thus we finally have our answer: 29 cans of paint!