The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section. That's
(change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.
Answer:
The scale factor is 3
Step-by-step explanation:
The width of A is 1, the width of B is 3
the length of A is 3, the length of B is 9 so the scale factor from A to B is 3
Answer:
Distance between the police station and the fire station be 4 miles
Step-by-step explanation:
Let distance between the police station and the fire station be x miles.
The distance between the library and the police station is 3 miles less than twice the distance between the police station and the fire station.
Distance between the library and the police station 
Also, distance between the library and the police station is 5 miles.

I don’t know the answer too hope you find some that can help
Answer: true.
If a quadrilateral is a parallelogram, it has two sets of opposite sides that are congruent. If you follow the picture attacheed, you see that AD equals BC and AB equals DC.
There is a theorem that says that If a quadrilateral is a parallelogram, it has<span> consecutive angles that are supplementary. Suplementary means that, those 2 angles together, form 180º.</span>