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sukhopar [10]
2 years ago
11

What are the coordinates of the image of (-3, -7) after the translation (x, y) - > (x-9, y + 9)? F (-6, 16) H (12, -2) G (6,

-16) J (-12, 2)
Mathematics
1 answer:
lana66690 [7]2 years ago
7 0

The coordinates of the image of (-3, -7) after the translation will be equal to .(-12,2)

<h3>What is translation?</h3>

The process of changing the location of the image on the coordinate system will be known as the translation. Here the image is translated as (x-9,y+9).

The given coordinate of the point is:- (-3,-7)

So the translation will be calculated as:-

=(x-9,y+9 )

=(-3-9,-7+9

=(-12,2)

Hence coordinates of the image of (-3, -7) after the translation will be equal to (-12,7)

To know more about translation follow

brainly.com/question/12861087

#SPJ1

 

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X f(x)<br> 2 18<br> 3 27<br> 4 36<br> 5 45
Ad libitum [116K]

Answer:

f(x) = 9x

Step-by-step explanation:

18=9×2

27=3*9

36=4*9

45=5*9

5 0
2 years ago
Find cube root of 175616 ??​
Tpy6a [65]

Answer:

56

Step-by-step explanation:

Cube root of 175616 by prime factorization method is 56

Solution:

To find cube root of 175616 by prime factorization method

A number that must be multiplied by itself three times to equal a given number is called cube root

Prime factorization method:

Prime factorization is a number written as the product of all its prime factors.

In order of finding cube root by prime factorization we use the following steps:

Step I : Obtain the given number

Step II : Resolve it into prime factors.

Step III : Group the factors in 3 in such a way that each number of the group is same

Step IV : Take one factor from each group

Step V : Find the product of the factors obtained in step IV. This product is the required cube root

Prime factorization of 175616:

\text{ prime factors of 175616 } = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 prime factors of 175616 =2×2×2×2×2×2×2×2×2×7×7×7

Thus we get,

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7}

3

175616

=

3

2×2×2×2×2×2×2×2×2×7×7×7

Make the groups of 3 of equal numbers

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{2 \times 2 \times 2 \times } \times \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{7 \times 7 \times 7}

3

175616

=

3

2×2×2

×

3

2×2×2×

×

3

2×2×2

×

3

7×7×7

So there are 4 equal groups. So from that group take one factor out

\sqrt[3]{175616} = 2 \times 2 \times 2 \times 7 = 56

3

175616

=2×2×2×7=56

Thus Cube root of 175616 by prime factorization method is 56

please mark me as a brainlist

3 0
3 years ago
What is the domain of ƒ(x) if ƒ(x) = 1 x – 4?
Alina [70]
The domain would negative infinity to positive infinity . Domain would be the smallest through the largest possibly value of X. If you also need the range it’s ( -4,infinity]
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3 years ago
At bright minds learning , 75% of employees work as instructors . If there are 300 employees at bright mind Learning , how many
Scilla [17]

Answer:

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Step-by-step explanation:

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3 0
4 years ago
Find all the values of x in the set of complex numbers that satisfy the following equation:
Fynjy0 [20]
Compute all the component integrals first:

I_1=\displaystyle\int_0^{\pi/4}2\sec x\,\mathrm dx=2\ln(\sqrt2+1)
I_2=\displaystyle\int_0^2\ln x\,\mathrm dx=2(\ln2-1)
I_3=\displaystyle\lim_{a\to\infty}\int_{-a}^a\frac{\mathrm dx}{x^2+1}=\pi

Now,

\sqrt2\approx1.4\implies \sqrt2+1\approx2.4
\implies \left\lceil I_1\right\rceil=2

e
\implies\left\lfloor I_2\right\rfloor=-1

\pi\approx3.14\implies\left\lceil I_3\right\rceil=4

So the given equation reduces to

\displaystyle\sum_{k=-1}^2\frac{\mathrm d}{\mathrm dx}x^{k+2}=1-4!
\dfrac{\mathrm dx}{\mathrm dx}+\dfrac{\mathrm dx^2}{\mathrm dx}+\dfrac{\mathrm dx^3}{\mathrm dx}+\dfrac{\mathrm dx^4}{\mathrm dx}=-23
4x^3+3x^2+2x+24=0

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5 0
3 years ago
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