To find out if a triangle is a right triangle, you can use the Pythagorean theorem(which can only be used for right triangles):
a² + b² = c² (c is the hypotenuse or the longest side) And you can plug in the side lengths into this equation. If they are the same number on both sides, it is a right triangle, if they are different numbers it is not a right triangle.
6.) a² + b² = c²
(4√3)² + (11)² = (13)²
(16(3)) + 121 = 169
48 + 121 = 169
169 = 169 It IS a right triangle
7.) a² + b² = c²
(5)² + (2√14)² = (9)²
25 + (4(14)) = 81
25 + 56 = 81
81 = 81 It IS a right triangle
8.) a² + b² = c²
(6)² + (√49)² = (√82)²
36 + 49 = 82
85 = 82 It is NOT a right triangle
9.) a² + b² = c²
(13)² + (2√39)² = (16)²
169 + (4(39)) = 256
169 + 156 = 256
325 = 256 It is NOT a right triangle
Answer:
a c and e
Step-by-step explanation:
I JUST FINISHED THE ASSIGNMENT
Answer:
11 hours she worked at the grocery store
Step-by-step explanation:
assuming,
the number of hours worked at tutoring = x
the number of hours worked at grocery store = y
which means,
the amount she made at tutoring = x* $15
the amount she made at grocery store = y*$9
we have 2 equations
<em>total number of hours</em>
1) x+y= 15
<em>total amount she earned</em>
2) x* $15+ y* $9= $159
From equation 1
x+y= 15
x=15-y
<em>we replace this x value in equation 2</em>
x* $15+ y* $9= $159
(15-y)* $15+ y* $9= $159
(15*15)- 15y+9y=159
225-6y=159
225-159=6y
66=6y
66/6=y
<u>11=y</u> <em>the number of hours she worked at grocery store. </em>
<em>we place y=11 in our derived x equation</em>
x=15-y
x=15-11
<u><em>x=4 </em></u><em>the number of hours she worked at tutoring. </em>
(2,3) so x=2, y=3 and h=(2^2+3^2)^(1/2)=√13
sina=3/√13, cosa=2/√13, tana=3/2
Afterwards multiply sina and cosa by √13/√13 and get sina=(3√13)/13 and cosa=(2√13)/13
