0.1[x+250]=5000
10(0.1[x+250]=5000
1[x+250]=50,000
x+250=50,000
-250 -250
x = 49,750
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
To find the area of a rectangle, multiple the width by the length.
(And simply the fractions for a simpler equation)
For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5
(3/4) • (8/5) = area
Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)
The area of piece A is 24/20
If you do the same for piece B:
(2/5) • (21/8) = area
The answer is 42/40
Answer:
Step-by-step explanation:
Evaluate
Thus, the answer is
<em>~Lenvy~</em>
Socratic said
(C) 4.5 times 10 Superscript 6 light bulbs
