<span>Evaluate 3{5 3[10 4 · 8]}
</span><span>3{5 3[10 4 · 8]}
</span>
=14400
If L is parallel to y = 4x + 1, then L must have the same slope. Thus, L has the form y = 4x + b
To figure out what "b" is, it is shown that point (0, -2) is on line L. So plug that into y = 4x + b, and we will see that b has to be equal to -2. Thus our equation of L is: y = 4x - 2
Now since P is a x-intercept, it has the coordinates: (x,0).
To figure out what x is, we need to solve:
0 = 4x - 2, solve:
2 = 4x
2/4 = x
1/2 = x
Thus point P is (1/2,0)
Step-by-step explanation:
2(x + 10) = 3x - 30
2x + 20 = 3x - 30
2x - 3x = -30 - 20
-x = -50
x = 50°
We shall use the formula for distance traveled:
s = ut + (1/2)at^2
where
u = initial velocity
t = time
a = acceleration.
Because
u = 0 (car starts from rest),
t = 10 s (travel tme),
a = 2 m/s^2 (acceleration), m
the di mstance traveled is
s = (1/2)*(2 m/s^2)*(10 s)^2 = (1/2)*2*100 = 100
Answer: 100 m
.
Given
area of the pillow = 144sq inchs
![No.\text{ of ribbon}=\text{ 4.}\sqrt{144}](https://tex.z-dn.net/?f=No.%5Ctext%7B%20of%20ribbon%7D%3D%5Ctext%7B%204.%7D%5Csqrt%7B144%7D)
Area of square = L X L
![\begin{gathered} Area=L^2 \\ 144=L^2 \\ \\ L=\sqrt{144} \\ \\ L=12m \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20Area%3DL%5E2%20%5C%5C%20144%3DL%5E2%20%5C%5C%20%20%5C%5C%20L%3D%5Csqrt%7B144%7D%20%5C%5C%20%20%5C%5C%20L%3D12m%20%5Cend%7Bgathered%7D)
Therefore,
![\begin{gathered} No.\text{ of ribbons = 4}\times12 \\ No.\text{ of ribbons = 48ribbons} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20No.%5Ctext%7B%20of%20ribbons%20%3D%204%7D%5Ctimes12%20%5C%5C%20No.%5Ctext%7B%20of%20ribbons%20%3D%2048ribbons%7D%20%5Cend%7Bgathered%7D)
Therefore, Number of ribbons = 48ribbons
Let's call the amount of quizzes Lauren will take in total as x.
Since the relationship is directly proportional, the ratio between quizzes and weeks should stay the same for different amount of weeks. This statement gives to us the following equation
![\frac{15}{3}=\frac{x}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B3%7D%3D%5Cfrac%7Bx%7D%7B4%7D)
Solving for x, we have
![\begin{gathered} \frac{15}{3}=\frac{x}{4} \\ 3\times x=15\times4 \\ 3x=60 \\ x=\frac{60}{3} \\ x=20 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B15%7D%7B3%7D%3D%5Cfrac%7Bx%7D%7B4%7D%20%5C%5C%203%5Ctimes%20x%3D15%5Ctimes4%20%5C%5C%203x%3D60%20%5C%5C%20x%3D%5Cfrac%7B60%7D%7B3%7D%20%5C%5C%20x%3D20%20%5Cend%7Bgathered%7D)
After attending 4 weeks of school this quarter, Lauren will take in total 20 quizzes.