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3 years ago

Write the coordinates for the given dilation

Mathematics

1 answer:

Olegator [25]3 years ago

5 0

<u>Answer:</u>

D $_o$ of Y = (-3/2, -1)

<u>Step-by-step explanation:</u>

We are given three points on the graph:

X (4, 0)

Y (3, 2)

Z (2, 2)

and the scale factor of dilation which is $-\frac{1}{2}$ .

Given that, we are to find the coordinates of Y after dilation. To find that, we will multiply the coordinates of the point Y with the scale factor.

Y = $(-\frac{1}{2}$ × $3$ , (-\frac{1}{2}[/tex] × $2)$

Y = $(-\frac{3}{2} , -1)$

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Anni [7]

The answer is -3 for the problem

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3 years ago

13. Round to higher foot, then Solve for volume in cubic yards.

Elenna [48]

Answer:

V = 11.4 cubic yards

Step-by-step explanation:

1 foot = 12 inches

1 yard = 36 inches

1 cubic yard = 46656 cubic inches

change the given values to inches by multiplying by 12

Length = 10'8" , round to higher foot

Length = 11*12 =

Length = 132 inches

Width = 6'4", round to higher foot

Width = 7*12

Width = 84 inches

Depth = 4'

Depth = 4*12 = 48 inches

The volume V = length x width x depth = 132 x 84 x 48 = 532224 cubic inches

divide by 46656 get cubic yards

V = 11.4 cubic yards

7 0

3 years ago

Compare the value of 495,123 and 63,129

Vesnalui [34]

63,219 is overall the lower value, but has the greater hundreds and ones place.

Hope this helps!

8 0

3 years ago

In ΔABC, a = 660 cm, b = 680 cm and c=100 cm. Find the measure of ∠B to the nearest degree.

scoundrel [369]

Answer:

m∠B = $97^{o}$ .

Step-by-step explanation:

Since the three sides of the triangle are given, then we apply cosine rule.

$b^{2}$ = $a^{2}$ + $c^{2}$ - 2ac Cos B

But, a = 660 cm, b = 680 cm, and c = 100 cm.

So that;

$680^{2}$ = $660^{2}$ + $100^{2}$ -2(660 x 100) Cos B

462400 = 435600 + 10000 - 132000 Cos B

462400 = 445600 - 132000 Cos B

132000 Cos B = 445600 - 462400

= -16800

Cos B = $\frac{-16800}{132000}$

= -0.1273

B = $Cos^{-1}$ -0.1273

= $97^{o}$

Thus, measure of ∠B is $97^{o}$ .

7 0

3 years ago

Read 2 more answers

Which pairs of quadrilaterals can be shown to be congruent using rigid motions?

Reil [10]

Answer:

Answer:

quadrilateral 1 and quadrilateral 2 NOT CONGRUENT

quadrilateral 1 and quadrilateral 3 CONGRUENT

quadrilateral 1 and quadrilateral 4 CONGRUENT

quadrilateral 2 and quadrilateral 3 NOT CONGRUENT

quadrilateral 2 and quadrilateral 4 NOT CONGRUENT

quadrilateral 3 and quadrilateral 4 CONGRUENT

Step-by-step explanation:

quadrilateral 1 and quadrilateral 2 NOT CONGRUENT

quadrilateral 1 and quadrilateral 3 CONGRUENT:

rigid motion: reflection

axis of reflection: y=x

quadrilateral 1 and quadrilateral 4 CONGRUENT:

rigid motions: translation and reflection

axis of reflection y=0

quadrilateral 2 and quadrilateral 3 NOT CONGRUENT

quadrilateral 2 and quadrilateral 4 NOT CONGRUENT

quadrilateral 3 and quadrilateral 4 CONGRUENT:

rigid motions: translation and reflection

axis of reflection: x=0

4 0

3 years ago