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Ahat [919]
3 years ago
7

Jason deposits $5 into his savings account twice a week for 6 weeks. How much money will he have saved after 6 weeks?

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

60

Step-by-step explanation:

amount of money deposited for one week= $10

no. of weeks= 6

amount= 6*10=60

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The sides of a square are 2 4/9 inches long. What is the area of the square?
Law Incorporation [45]
<span>2 4/9 = 22/9

Area of square = a^2 = (22/9)^2 = 484/81 square inches.

hope that helps</span>
5 0
3 years ago
Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
A local 4-H club surveyed its members, and the following information was obtained: 14 members had rabbits, 10 had goats, 4 had b
Fiesta28 [93]
A) 68.29%
B) 34.15%
C) 24.39%
8 0
3 years ago
What is the image point of (3, 8) after a translation right 3 units and down 5 units
shusha [124]

Answer:

<h3>               (6, 3)</h3>

Step-by-step explanation:

Translation right (or left) means change of the x-coordinate.

Translation down (or up) means change of the y-coordinate.

(3, 8)   →    (3+3, 8-5) = (6, 3)

4 0
3 years ago
Jake has a summer job as a photographer at an amusement park. He wants to save$3500 . He must choose whether to sell large photo
avanturin [10]

Question: Jake has a summer job as a photographer at an amusement park. He wants to save $3500 . He must choose whether to sell large photos or small photos. For each photo, he will earn the amounts shown in the table. How many of each kind of photo will he need to sell to reach his goal of $3500 ?

Answer: With the added information from the comments, Small Photos cost $12 and Large Photos cost $15.

We want to figure out how many photos of each size Jake will need to earn a total of $3500.

To figure out how many Small Photos Jake needs to sell, you can divide the amount he wants to save by the cost of the small photos:

On my calculator, 3500÷12 equals roughly 291.6666667. Realistically that number doesn't make sense in this context, so it's safe to round that to the nearest whole number, which would be 292. Selling 292 small photos will earn Jake $3504. It's okay that he's earned more than he wanted to save because it's safer to earn more instead of not earning the amount he needs. If we decided to stick with 291 small photos, Jake would have only earned $3492, which isn't enough.

In conclusion, Jake will need to sell 292 small photos.

To figure out how many Large Photos Jake needs to sell, the process is the same for the Small Photos. Again, you divide the amount Jake needs to save by the cost of the Large Photos:

3500÷15= 233.3333333 ... the threes keep repeating. As mentioned before, this number realistically doesn't make sense, so we must round again to the next whole number. That would be 234 Large Photos. By selling 234 Large Photos Jake will earn $3510 instead of $3495 if he had only sold 233 Large Photos.

(Hope this helps :). Please let me know if there's any confusion in my explanation)

7 0
3 years ago
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