I'm guessing just to show that you did your work to get the answer.
Answera:The answer is 0.3333333333 repeated
Step-by-step explanation:5/6 is 0.8333333 repeated divided by 5/2 which is 2.5 which when divided is 0.333333333 repeated.
X = 9 sorry if x isnt what youre looking for
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Cross multiply and set it up like this.
1800 X
------- • -------
80 24
Multiply 1800•24
Then divide by 80 and you get 540.
