Which of the following equationa apply to line below
2 answers:
Answer:
b and d
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
m is the slope and (a, b) a point on the line
Calculate m using the slope formula
m =
with (x₁, y₁ ) = (- 3, 6) and (x₂, y₂ ) = (- 2, 2) ← 2 points on the line
m = = - 4
Using (a, b ) = (- 3, 6 ), then
y - 6 = - 4(x - (- 3)), that is
y - 6 = - 4(x + 3) → d
Using (a, b ) = (- 2, 2 ), then
y - 2 = - 4(x - (- 2)) , that is
y - 2 = - 4(x + 2) →b
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Answer:
Step-by-step explanation:
From the question, we are given;
- The equation y = 3x + 2
- A point (-1, -2)
We are required to determine the equation of a line parallel to the given line and passing through the point (-1, -2)
- We are going to determine the gradient of the line first; when an equation is written in the form of y = mx + c, where m is the gradient.
y = 3x + 2, m₁ = 3
- But, m₁ = m₂ for parallel lines
- Therefore, the gradient of the line in question, m₂ is 3
- With the gradient, m₂=3 , and a point (-1, -2) we can get its equation;
Taking another point (x, y)...
Then;
Therefore; the equation of the line is