Answer:
1/250 W/m² or 0.004 W/m² or 4 mW/m²
Step-by-step explanation:
The cargo worker is (50 m)/(1 m) = 50 times the reference distance. The intensity varies as the inverse of the square of the distance, so will be ...
(1/50)²×(10 W/m²) = 10/2500 W/m² = 1/250 W/m²
This might be more conveniently written as 4 mW/m².
Answer:
Below.
Step-by-step explanation:
f(x) = a(x - j)^2 + k is the standard vertex form where (j, k) is the vertex,
f(x) = (x + 3)^2 + 4
Comparing this to the standard form we see that:
vertex = (-3, 4)
Suppose we have the repeat decimal 0.123232323.... or 0.123 with a line over the repeated part (check the diagram)
- The first thing we need to do is identify the part of the decimal that repeats, 23 in our case.
- Second, we are going to assign a variable to our original decimal:
![x=0.123232323...](https://tex.z-dn.net/?f=x%3D0.123232323...)
.
- Third, we are going to multiply both sides by a power of ten whose denominator will be the number of repeating digits. We know that we have 2 repeating digits (23), so we are going to multiply both sides by
![10 ^{2}](https://tex.z-dn.net/?f=10%20%5E%7B2%7D%20)
, and
![10 ^{2}](https://tex.z-dn.net/?f=10%20%5E%7B2%7D%20)
is just 100; therefore we get:
![100x=(100)(0.123232323...)](https://tex.z-dn.net/?f=100x%3D%28100%29%280.123232323...%29)
![100x=12.32323232...](https://tex.z-dn.net/?f=100x%3D12.32323232...)
- fourth, subtract our original equation from the second step from the one from above:
![\left \{ {{100x=12.323232...} \atop {-x=1.123232} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7B100x%3D12.323232...%7D%20%5Catop%20%7B-x%3D1.123232%7D%20%5Cright.%20)
Now we can cancel the repeated decimals to get:
![\left \{ {{100x=12.3} \atop {-x=0.1}} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7B100x%3D12.3%7D%20%5Catop%20%7B-x%3D0.1%7D%7D%20%5Cright.%20)
![99x=12.2](https://tex.z-dn.net/?f=99x%3D12.2)
![x= \frac{12.2}{99}](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B12.2%7D%7B99%7D%20)
- Last but not least multiply both numerator and denominator by a power of ten equals to the decimal digits in the numerator:
![x= \frac{12.2(10 ^{1}) }{99(10 ^{1}) } = \frac{122}{990}](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B12.2%2810%20%5E%7B1%7D%29%20%7D%7B99%2810%20%5E%7B1%7D%29%20%7D%20%3D%20%5Cfrac%7B122%7D%7B990%7D%20)
We now know how to convert a repeating decimal to a fraction.
If your equation boils down to 12=12, then that means the variables you use don't even matter. Not only would this have infinitie solutions, but all solutions.
Answer:
After taking the first exam, 15 of the students dropped the class. The value 15 describes a characteristic of a population - first choice.