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3 years ago

If the scale factor between two circles is 2x/5y, what is the ratio of their areas?

2 answers:

6 0

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\$

$\bf \cfrac{s}{s}=\cfrac{2x}{5y}\qquad \textit{then the areas ratio is }\cfrac{s^2}{s^2}\implies \cfrac{(2x)^2}{(5y)^2}\implies \cfrac{4x^2}{25y^2}$

Korolek [52]3 years ago

6 0

Answer:

<h2>The answer is D on eg </h2>

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Now, for 90% confidence level, from the table we know that $Z=1.645$ .

The formula for the interval range of proportion of students is :

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Plugging in the values we get:

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