Let
be the number of students who eat cauliflower.
Therefore,
.
Let
be the total number of students surveyed.
Therefore, 
Thus, 

Now, for 90% confidence level, from the table we know that
.
The formula for the interval range of proportion of students is :

Plugging in the values we get:

Thus, Jane is 90% confident that the population proportion p, for students who eat cauliflower in her campus is between 5.398% and 15.114% (after converting the answer we got to percentage).
Calculate this:
V = (4 ft)(6 ft)(2.67 ft)
= (24 ft^2)(2.67 ft) = 64.08 ft^3
B. I do know if it’s a triangle but 180 degrees is what you need to get to so 104+76=180
Answer is 64 and a factor is 6/4 .
Answer:
A=30
Step-by-step explanation:
Set your equation up as following:
180=90+(x+37)+(x+67)
180=90+37+67+2x
180-90-37-67=2x
-14=2x
-14/2=x
-7=x
Angle A = x+37
A=-7+37
A=30