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tensa zangetsu [6.8K]
3 years ago
6

If the scale factor between two circles is 2x/5y, what is the ratio of their areas?

Mathematics
2 answers:
makkiz [27]3 years ago
6 0
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{s}{s}=\cfrac{2x}{5y}\qquad \textit{then the areas ratio is }\cfrac{s^2}{s^2}\implies \cfrac{(2x)^2}{(5y)^2}\implies \cfrac{4x^2}{25y^2}
Korolek [52]3 years ago
6 0

Answer:

<h2>The answer is D on eg </h2>

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Let x be the number of students who eat cauliflower.

Therefore, x=4.

Let n be the total number of students surveyed.

Therefore, n=39

Thus, \hat p=\frac{4}{39} =0.10256

Now, for 90% confidence level, from the table we know that Z=1.645.

The formula for the interval range of proportion of students is :

p= \hat p\pm Z\sqrt{\frac{\hat p(1-\hat p)}{n}}

Plugging in the values we get:

p=0.10256\pm 1.645\sqrt{\frac{0.10256(1-0.10256)}{39}}=0.10256\pm 0.04858=0.15114, 0.05398

Thus, Jane is 90% confident that the population proportion p, for students who eat cauliflower in her campus is between 5.398% and 15.114% (after converting the answer we got to percentage).

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