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3 years ago

6

Each year, Paul's aunt gives him a birthday gift of $100 in cash. Paul deposits the money into an account that earns simple inte

rest at a rate of 4%. Paul makes no withdrawals. How much interest has his account earned after 7 years?

1 answer:

sattari [20]3 years ago

4 0

Answer:

100 *4% then divided 7 the number you got

Step-by-step explanation:

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The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab

Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$\pi = 0.25$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when $M = 0.1$

So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}$

$0.1\sqrt{n} = 2.575{0.25*0.75}$

$\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}$

$(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}$

$n = 124.32$

Rounding up

The minimum sample size needed is 125.

5 0

3 years ago

| x-3 | < x-3<br><br> can someone give a step by step process on how to do this?

statuscvo [17]

Answer:

There are no solutions to the inequality.

Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)

2. Solve each equation separately

(a) Equation (1)

$\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}$

(b) Equation (2)

$\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &$

For example, if x = 0, we get

|0 - 3| < 0 - 3 or

3 < -3

4 0

3 years ago

The tree house. Juanita is building is two two wholes and 2 1 / 2 ft from the ground the tree house that Rosa is building is fiv

Molodets [167]

Answer: 2/21 hope this helps : )

Step-by-step explanation: ok the way you do this s 21/2 times five then simplify, 5 is the GCF of 105 and 10 and when you simplify you get 21/2 flip the denominator with the divisor and you get 2/21

5 0

2 years ago

Question 10: Each tablet in a bottle of 30 costs the pharmacy $4.60. The pharmacy has additional costs including supplies and sh

valentinak56 [21]

The pharmacy should charge $201.6 for the entire bottle

Cost price refers the price the seller bought the product

Selling price refers to the price the seller sells to the consumer.

Profit refers to the money earned by the seller above the cost price

Loss refers to the money paid by the seller above the cost price.

Profit= SP-CP

CP=30X$4.60=$138

TOTAL EXPENSES=$138+30X$1.40

= $180

FOR PROFIT OF 12%,the seller must sell in= $180(1+12/100)

=$201.6

Therefore,the pharmacy should charge $201.6 for the entire bottle to make a profit of atleast 12%

Learn more about profit and loss,

brainly.com/question/19104371

#SPJ10

8 0

1 year ago

A cat keeps eating to gain weight while a dog keeps doing exercise.Later, the cat's weight increases by 20% and the dog's weight

lesya [120]

Answer:

Step-by-step explanation:

We will call the dog's original weight d and the cat's c. according to the problem 1.2c=.9d

1.2c is the cat's weight increased by 20% and .9d is the dog's weight decreased by 10% Now we just solve this with algebra for the dog's original weight.

1.2c=.9d

(1.2/.9)c = d

(4/3)c = d

Now, this tells us that the dog's original weight was 4/3 of the cat's.or about 33.33% larger

It kinda looks like the question is then asking what the cat's current weight is in comparison to the dog's original. If that's the case we need just one more step. We want the dog's original weight and the cat's current weight in terms of the same variable. Well, we have that.

Current cat = 1.2c or 6/5, since we have the other in fractional form.

original dog = (4/3)c

Now, what do we multiply the first to get to the second? Well, we need common denominators. 15 is the lcm of 3 and 5, so we'll use that.

6/5 = 18/15 and 4/3 = 20/15

Nowwe want to know what we have to multiply 18 by to get to 20. some algebra will find that.

18x=20

x = 20/18

x = 10/9

that's about 1.11, so the dog's original weight is about 11% higher than the cat's current weight.

Hopefully that's the answer it wanted, if not or if there is something you didn't understand let me know.

7 0

3 years ago