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3 years ago

Using Rigid motion, explain in detail, why triangle ABC must be congruent to triangle DEF

1 answer:

7 0

Using rigid motion, both of these triangles will be congruent. The reason is because rigid motions include reflections, translations, and rotations.

None of these transformations will affect the size or shape of the figure, therefore keeping them congruent.

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there were a total of twenty-one baseball games during the three month season, and four were played at night. If the game are eq

kicyunya [14]

If there were a total of 21 games played over 3 months, you divide 21 by 3.

Your answer is 7 games were played each month.

The information about how many games were played at night is useless. It's just thrown in there to confuse you. :)

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3 years ago

Please help need it ASAP!!!✋

FromTheMoon [43]

Answer: Its a little blurry I cant se

Step-by-step explanation:

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2 years ago

For a continuous random variable x, the height of the function at x is a. 0.50, since it is the middle value. b. a value less th

gogolik [260]

Answer:

Answer is a continuous random variable x the height of the function named the probability density function f(x)

Step-by-step explanation:

A continuous random variable takes infinite number of possible values.

example include height , weight amount of sugar in an orange time required to run a mile.

Continues random variable named probability function f(x).

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3 years ago

Skyler goes to a school which has 1000 students in it. She asks 40 random students whether they like the new 8.30am start to the

fenix001 [56]

Answer:

100/40=25

25*30=750

so 750 students would dislike the new starting time.

I really hope this was correct and helpful. I tried my best.

7 0

3 years ago

I don’t understand this someone pls help me! (Question 10)

Likurg_2 [28]

Answer:

a. f(n) = n(n+1)/2

b. 351

c. 19

d. no; n would not be an integer for f(n) = 17.

Step-by-step explanation:

a. The terms are 1, 3, 6, 10, ...

Each term has the term number added to the previous term. That is, first differences are 3-1 = 2, 6-3 = 3, 10-6 = 4. These differences have a constant difference of 1.

When the 2nd differences are constant, a 2nd degree polynomial can describe the sequence. It is a little bit of trouble to find that polynomial.

For the polynomial ...

$f(n)=an^2+bn+c$

We can substitute values for n and f(n) to get 3 equations in 3 unknowns:

$1=a\cdot1^2+b\cdot1+c\\\\3=a\cdot2^2+b\cdot2+c\\\\6=a\cdot3^2+b\cdot3+c$

Solving these equations by your favorite method gives ...

(a, b, c) = (1/2, 1/2, 0)

That is, the function representing the relationship is ...

f(n) = n(n+1)/2 . . . . the function describing the relationship

b. f(26) = 26(27) = 13(27) = 351 . . . . the number of squares in term 26

c. The number of the term having 190 squares can be found by solving ...

n(n +1)/2 = 190

n(n +1) = 380 = 19(20)

The 19th term will have 190 squares.

d. Terms 5 and 6 are 15 and 21.

17 is not the value of one of the terms in this sequence.

6 0

2 years ago