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2 years ago

1. George joins a gym. He pays $25 to sign up and then $15 per month.

Mathematics

2 answers:

DIA [1.3K]2 years ago

7 0

Answer:

100 dollars

Step-by-step explanation:

First you multiply how much it is each month by how many months.

5x15=75

Then you add the money he has to pay to sign up. So,

75+25=100

Zigmanuir [339]2 years ago

5 0

Answer:

I believe the answer would be $100

Step-by-step explanation:

1. He already payed the $25 so he doesn't need to pay that anymore

2. If he's paying $15 a month you would have to multiply 15 by 5 because he went for 5 months

3. for the five months he payed $75, so after that you would have to add the additional $25 to the $75 get the answer of $100

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Two customers went to a post office to buy postcards and large envelopes. Each postcard

astraxan [27]

The right answer is Option A.

Step-by-step explanation:

Let,

x be the postcards

y be the large envelops

According to given statement;

14x+5y=12 Eqn 1

10x+15y=24.80 Eqn 2

Multiplying Eqn 1 by 3;

$3(14x+5y=12)\\42x+15y=36\ \ \ Eqn \ 3$

Subtracting Eqn 2 from Eqn 3;

$(42x+15y)-(10x+15y)=36-24.80\\42x+15y-10x-15y=11.20\\32x=11.20\\$

Dividing both sides by 32

$\frac{32x}{32}=\frac{11.20}{32}\\x=0.35$

Putting x=0.35 in Eqn 1;

$14(0.35)+5y=12\\4.90+5y=12\\5y=12-4.90\\5y=7.10$

Dividing both sides by 5

$\frac{5y}{5}=\frac{7.10}{5}\\y=1.42$

Therefore, one large envelope costs $1.42

The right answer is Option A.

Keywords: linear equations, subtraction

Learn more about linear equations at:

#LearnwithBrainly

4 0

3 years ago

(please help me)

Jobisdone [24]

Answer:

8/14

Step-by-step explanation:

there are 5 odd numbers and 3 numbers are coloured red

7 0

2 years ago

a file that is 278 megabytes is being downloaded. If downloaded is 14.1% complete, how many megabytes been downloaded? To round

Gekata [30.6K]

14.1% of 278 is 39.2. So 39.2 megabytes have been downloaded.

4 0

3 years ago

Read 2 more answers

2.Solve the following quadratic equations<br> i. 9x^2 - 1/16<br> ii. 2h^2 - 3h - 27

Juli2301 [7.4K]

$i)~9x^2-\dfrac{1}{16}=0\iff9x^2=\dfrac{1}{16}\iff x^2=\dfrac{1}{9\cdot16}\iff \\\\x^2=\dfrac{1}{144}\iff x=\pm\sqrt{\dfrac{1}{144}}=\pm\dfrac{1}{12}\Longrightarrow\boxed{x=\pm\dfrac{1}{12}}$

$ii)~2h^2-3h-27=0\\\\\Delta=b^2-4ac\to \Delta=(-3)^2-4\cdot2\cdot(-27)\to\Delta=9+216=225\\\\
\Longrightarrow h=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-(-3)\pm\sqrt{225}}{2\cdot2}=\dfrac{3\pm15}{4}\\\\\begin{cases}h_1=\dfrac{3+15}{4}=\dfrac{18}{4}\iff \boxed{h_1=\dfrac{9}{2}}\\h_2=\dfrac{3-15}{4}=\dfrac{-12}{4}\iff\boxed{h_2=-3}\end{cases}$

4 0

3 years ago

a square garden has a diagonal of 12 m. What is the perimeter of the garden? Express in simplest radical form

lianna [129]

Answer:

The perimeter of the garden, in meters, is $24\sqrt{2}$