Question

Suppose there is a 3Mbps uplink and 10Mbps downlink between a geostationary satellite and the base station on earth. If the propagation speed is the speed of light (3 * 10^8 m/sec), the packet size is 20Mb, and the distance from the satellite to earth is 36,000 km, what is the uplink propagation delay of the link in milliseconds

Answer 1

Answer:

$120\ \text{ms}$

Explanation:

Distance between the satellite and Earth = $36000\ \text{km}$

Speed of light = $3\times 10^8\ \text{m/s}$

Propagation delay is given by distance by the speed of light

$\dfrac{36000\times 10^3}{3\times 10^8}$

$=0.12\ \text{s}\times 10^3$

$=120\ \text{ms}$

The uplink propagation delay of the link is $120\ \text{ms}$.