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liberstina [14]
3 years ago
14

Factor k 2 + 8k + 15. answers. (k + 1)(k + 15) (k + 8)(k + 7) (k + 3)(k + 5)

Mathematics
2 answers:
saw5 [17]3 years ago
6 0
<span>k 2 + 8k + 15
= (k + 5)(k + 3)
answer is </span><span>(k + 3)(k + 5) (last choice)</span>
astra-53 [7]3 years ago
3 0
K² + 8k + 15 = (k+3)(k+5)

Answer is C
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3 0
3 years ago
Express 3500 in scientific notation that indicates it has two significant digits
arsen [322]

Hey there!

“3500 in scientific notion”

In order for you to find out your answer you have to move your decimal THREE places to your left. If you solve this, you should’ve gotten: 3.500

The “00” in the result we received is invisible so we don’t have to worry about right now in the equation to solve for your answer

Solve what you have ⬆️ ..

Answer: 3.5 × 10³

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

6 0
3 years ago
Solve the equation. x+6=x
Daniel [21]
E. no solution. hope this helps! :)
8 0
3 years ago
Read 2 more answers
Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

4 0
1 year ago
4x+3y=32 <br> 4x+y=16<br><br> work out x and y pleaseeeeeee
Marrrta [24]

Answer:

The answer is xy=16-4 and xy=12

3 0
3 years ago
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