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olga nikolaevna [1]
3 years ago
12

Please can’t you help me!! REALY FAST PLEASE

Mathematics
1 answer:
olganol [36]3 years ago
6 0

Answer:

65%

Step-by-step explanation:

this is because the decrease of price is 247 amd if u divide by original its 65%

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The joint F.D.P of a bivariate VA (X, Y) is given
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Answer:

2

Step-by-step explanation:

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3 years ago
GEOMETRY PEOPLE PLEASE HELP ME!!!!!!!!!!!!!!!!! I WILL GIVE BRAINLIEST!
IrinaVladis [17]

\Delta KLJ\sim\DeltaNPM (AAA) Corresponding angles are congruent.

Therefore, the sides of the triangles are proportional:

\dfrac{4x-4}{20}=\dfrac{30}{25}    cross multiply

25(4x-4)=(20)(30)    use distributive property

(25)(4x)+(25)(4)=600\\\\100x+100=600    subtract 100 from both sides

100x=500     divide both sides by 100

x=5

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\Delta PQR\cong\Delta STU (SAS)

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

Therefore we have the equation:

3y-2=y+4\qquad|+2\\\\3y=y+6\qquad|-y\\\\2y=6\qquad|:2\\\\y=3

The perimeter of △PQR:

P=4+6+3y-2=8+3y

Substitute the value of y to the expression:

P=8+3(3)=8+9=17\ ft

7 0
3 years ago
Can someone please help me with number 6?
Vlad1618 [11]

Step-by-step explanation:

substitute a with 2 and b with 3

2x+3

because it's the same equation it should just be an equal sign.

8 0
2 years ago
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4. a) A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If t
Klio2033 [76]

First part of question:

Find the general term that represents the situation in terms of k.

The general term for geometric series is:

a_{n}=a_{1}r^{n-1}

a_{1} = the first term of the series

r = the geometric ratio

a_{1} would represent the height at which the ball is first dropped. Therefore:

a_{1} = k

We also know that the ball has a rebound ratio of 75%, meaning that the ball only bounces 75% of its original height every time it bounces. This appears to be our geometric ratio. Therefore:

r=\frac{3}{4}

Our general term would be:

a_{n}=a_{1}r^{n-1}

a_{n}=k(\frac{3}{4}) ^{n-1}

Second part of question:

If the ball dropped from a height of 235ft, determine the highest height achieved by the ball after six bounces.

k represents the initial height:

k = 235\ ft

n represents the number of times the ball bounces:

n = 6

Plugging this back into our general term of the geometric series:

a_{n}=k(\frac{3}{4}) ^{n-1}

a_{n}=235(\frac{3}{4}) ^{6-1}

a_{n}=235(\frac{3}{4}) ^{5}

a_{n}=55.8\ ft

a_{n} represents the highest height of the ball after 6 bounces.

Third part of question:

If the ball dropped from a height of 235ft, find the total distance traveled by the ball when it strikes the ground for the 12th time. ​

This would be easier to solve if we have a general term for the <em>sum </em>of a geometric series, which is:

S_{n}=\frac{a_{1}(1-r^{n})}{1-r}

We already know these variables:

a_{1}= k = 235\ ft

r=\frac{3}{4}

n = 12

Therefore:

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{1-\frac{3}{4} }

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{\frac{1}{4} }

S_{n}=(4)(235)(1-\frac{3}{4} ^{12})

S_{n}=910.22\ ft

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Y=-3/4x+12
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Those are the answers
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