Answer:
Wyzant
ALGEBRA WORD PROBLEM
Dorian S. asked • 06/28/17
THREE LINEAR EQUATIONS WITH THREE VARIABLES
A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 25%,
and the third contains 70%. He wants to use all three solutions to obtain a mixture of 40 liters containing 45%
acid, using 2 times as much of the 70% solution as the 25% solution. How many liters of each solution should be used?
How to set up as three linear equations to find the answer?
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Arthur D. answered • 06/28/17
TUTOR 4.9 (67)
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set up 2 equations
the first equation...
15%*x+25%*y+70%*2y=45%*40
0.15x+0.25y+1.4y=0.45*40
0.15x+1.65y=18
multiply all terms by 100
15x+165y=1800
divide all terms by 15
x+11y=120
the second equation...
x+y+2y=40
x+3y=40
x=40-3y
substitute into the first equation x+11y=120
40-3y+11y=120
40+8y=120
8y=120-40
8y=80
y=80/8
y=10 liters
x+3*10=40
x+30=40
x=40-30
x=10 liters
10 liters of 15%, 10 liters of 25%, and 20 liters of 70%
check:
10*15%=1.5
10*25%=2.5
20*70%=14
1.5+2.5+14=18
18/40=9/20=45/100=45%
45%*40=18
hope it helps
please mark brainliest
Answer:
P[J(y)] = 2/3 * J(y) -2
Step-by-step explanation:
The area of the square is obtained by taking the square of the length of one side. Since it is said that the area of the square is less than 100 m^2, taking the square root of that where: sqrt (100) = 10, the side of that square should be less than 10 as well. Among the choices, D. 0 <y <10 (where y = length of side of square) is the correct answer.
Answer:
x ≥ -5
Step-by-step explanation:
If we have a translation to left c units, we write " x + c " in the function, and
If we have a translation to right c units, we write " x - c" in the function
If we have vertical translation up b units, we "add b to the function", and
If we have vertical translation down b units, we "subtract b to the function"
The parent function is 
Since translation left 5 units and up 3 units, we can write:
The domain is affected by the square root sign and we know the number under the square root CANNOT be negative, so we can say:
x + 5 ≥ 0
x ≥ -5
This is the domain.
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
60 seconds x 60 minutes = 3,600 seconds per hour
3,600 seconds per hour x 24 hours = 86,400 seconds per day.
The light flashes 5 times every 10 seconds:
5 flashes / 10 seconds = 1 flash every 2 seconds
86,400 seconds / 2 seconds = 43,200 flashes per day.
